java - Spring MVC Hibernate Spring Security 登录

Question

我正在尝试通过登录使用 spring security。

<%@page contentType="text/html" pageEncoding="UTF-8"%>
<%@ taglib prefix="form" uri="http://www.springframework.org/tags/form" %>
<%@ taglib prefix="spring" uri="http://www.springframework.org/tags" %>
<%@ taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c" %>

    <form:form action="j_spring_security_check" method="POST" modelAttribute="loginForm">
        <table>
            <tr>
                <td colspan="2" align="center">Already have an account - Login</td>
            </tr>
            <tr>
                <td>Email</td>
                <td><form:input path="emailID" /> <form:errors path="emailID" class="error" /></td>
            </tr>
            <tr>
                <td>Password</td>
                <td><form:password path="password" /> <form:errors path="password" class="error" /></td>
            </tr>
            <tr>
                <td colspan="2" align="center"><input type="submit" value="Login" /></td>
            </tr>   
            <tr>
                <td colspan="2" align="center">
                    <a href="${pageontext.request.contextPath }/forgotpassword">Forgot Password</a>
                </td>
            </tr>                                   
        </table>                                        
    </form:form>
    <span class="error">${loginMessage}</span>

spring-security.xml

<beans:beans xmlns="http://www.springframework.org/schema/security"
    xmlns:beans="http://www.springframework.org/schema/beans" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://www.springframework.org/schema/beans
    http://www.springframework.org/schema/beans/spring-beans.xsd
    http://www.springframework.org/schema/security
    http://www.springframework.org/schema/security/spring-security.xsd">

    <!-- enable use-expressions -->
    <http auto-config="true" use-expressions="true">
        <intercept-url pattern="/admin**" access="hasRole('ROLE_admin')" />

        <!-- access denied page -->
        <access-denied-handler error-page="/403" />
        <form-login 
            login-page="/login" 
            default-target-url="/index"
            authentication-failure-url="/login?error" 
            username-parameter="username"
            password-parameter="password" />
        <logout logout-success-url="/login?logout" />
        <!-- enable csrf protection -->
        <csrf />
    </http>

    <beans:bean id="userAuthenticationProviderImpl" class="com.pir.authentication.UserAuthenticationProviderImpl" />

    <authentication-manager>
        <authentication-provider user-service-ref="userAuthenticationProviderImpl" >
            <password-encoder hash="plaintext" />    
        </authentication-provider>
    </authentication-manager>

</beans:beans>

UserAuthenticationProviderImpl.java

@Component(value = "authenticationProvider")
public class UserAuthenticationProviderImpl implements
        UserAuthenticationProvider {

    UserFunctionsService userFunctionsService;

    @Autowired(required=true)
    @Qualifier(value="userFunctionsService")
    public void setUserFunctionsService(UserFunctionsService userFunctionsService)
    {
        this.userFunctionsService = userFunctionsService;
    }

    /* (non-Javadoc)
     * @see com.pir.authentication.UserAuthenticationProvider#authenticate(org.springframework.security.core.Authentication)
     */
    @Override
    public Authentication authenticate(Authentication authentication) {
        // TODO Auto-generated method stub

        Users users = (Users) this.userFunctionsService.getUserDetails(authentication.getPrincipal().toString());

        if(users == null)
            throw new UsernameNotFoundException(String.format("Invalid credentials", authentication.getPrincipal()));

        String suppliedPasswordHash = authentication.getCredentials().toString();

        if(users.getPassword().equals(suppliedPasswordHash)){
            throw new BadCredentialsException("Invalid credentials");
        }
        UsernamePasswordAuthenticationToken token = new UsernamePasswordAuthenticationToken(users, null);

        return token;
    }

}

用户.java

@Entity
@Table(name = "users")
public class Users {

    @NotNull
    @Id
    @Column(name = "userID")
    private int userID;

    @NotNull
    @Size(min=3, max=50)
    @Pattern(regexp = ".+@.+\\.[a-z]+")
    @Column(name = "emailID")
    private String emailID;

    @NotNull
    @Size(min=3, max=50)
    @Column(name = "firstName")
    private String firstName;

    @NotNull
    @Size(min=3, max=50)
    @Column(name = "lastName")
    private String lastName;

    @NotNull
    @Size(min=3, max=50)
    @Column(name = "password")
    private String password;

    @NotNull
    @Column(name = "mobileNo")
    private String mobileNo;


    @Column(name = "imageURL")
    private String imageURL;

    @NotNull
    @DateTimeFormat(pattern="MM/dd/yyyy")
    @Column(name = "dateOfBirth")
    private String dateOfBirth;

    @NotNull
    @Column(name = "gender")
    private String gender;

    @NotNull
    @Column(name = "userType")
    private String userType;

    @Lob
    private MultipartFile image;

        //getters and setters
}

pir-servlet.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:p="http://www.springframework.org/schema/p"
    xmlns:tx="http://www.springframework.org/schema/tx"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="
        http://www.springframework.org/schema/beans     
        http://www.springframework.org/schema/beans/spring-beans.xsd
        http://www.springframework.org/schema/context 
        http://www.springframework.org/schema/context/spring-context.xsd
        http://www.springframework.org/schema/tx
        http://www.springframework.org/schema/tx/spring-tx.xsd
        http://www.springframework.org/schema/mvc
        http://www.springframework.org/schema/mvc/spring-mvc-4.1.xsd"
    xmlns:mvc="http://www.springframework.org/schema/mvc">

    <context:annotation-config />

    <context:component-scan base-package="com.pir" />
    <mvc:annotation-driven />
    <tx:annotation-driven transaction-manager="myTransactionManager" />

    <bean id="myTransactionManager" class="org.springframework.orm.hibernate4.HibernateTransactionManager">
        <property name="sessionFactory" ref="sessionFactory" />
    </bean>

    <bean id="userFunctionsDAO" class="com.pir.dao.UserFunctionsDAOImpl" />
    <bean id="userFunctionsService" class="com.pir.service.UserFunctionsServiceImpl" />

    <bean id="multipartResolver" class="org.springframework.web.multipart.commons.CommonsMultipartResolver">
        <property name="maxUploadSize" value="1048576" />
    </bean>

<bean id="sessionFactory"
        class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
        <property name="dataSource" ref="dataSource" />
        <property name="configLocation">
            <value>classpath:hibernate.cfg.xml</value>
        </property>
        <property name="hibernateProperties">
            <props>
                <prop key="hibernate.dialect">${jdbc.dialect}</prop>
                <prop key="hibernate.show_sql">true</prop>
            </props>
        </property>
    </bean>

    <bean id="dataSource"
    class="org.springframework.jdbc.datasource.DriverManagerDataSource"
    p:driverClassName="com.mysql.jdbc.Driver"
    p:url="jdbc:mysql://localhost:3306/pir"
    p:username="root"
    p:password="user" />

    <bean id="tilesViewResolver"
        class="org.springframework.web.servlet.view.UrlBasedViewResolver">
        <property name="viewClass">
            <value>
                org.springframework.web.servlet.view.tiles3.TilesView
            </value>
        </property> 
    </bean>
    <bean id="tilesConfigurer"
        class="org.springframework.web.servlet.view.tiles3.TilesConfigurer">
        <property name="definitions">
            <list>
                <value>/WEB-INF/tiles.xml</value>
            </list>
        </property>
    </bean>

</beans>

当我尝试登录时，我希望登录成功或失败，但它给出了 HTTP Status 404 - 错误。这是我第一次尝试实现 spring security，所以对它了解不多。我在这段代码中做错了什么？

Answer 1

你还记得在 web.xml 中设置 spring 安全过滤器链吗？

<!--  Spring security filter -->
  <filter>
    <filter-name>springSecurityFilterChain</filter-name>
    <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
  </filter>
  <filter-mapping>
    <filter-name>springSecurityFilterChain</filter-name>
    <url-pattern>/*</url-pattern>
  </filter-mapping>

这可能是原因，但您的提供程序实现中存在一些错误。

 if(users.getPassword().equals(suppliedPasswordHash)){
            throw new BadCredentialsException("Invalid credentials");
        }
        UsernamePasswordAuthenticationToken token = new UsernamePasswordAuthenticationToken(users, null);

首先if里的条件不对，这个应该正好相反:

 if(!users.getPassword().equals(suppliedPasswordHash)){
            throw new BadCredentialsException("Invalid credentials");
        }

创建 UsernamePasswordAuthenticationToken 的下一行必须不同，一旦用户通过身份验证，您必须在调用构造函数时创 build 置 GrantedAuthorities 的 token 。如果user中的userType字段是匹配spring-security中指定的ROLE_admin的Authority，则必须做更多这样的事情:

Collection<GrantedAuthority> authorities = new ArrayList<GrantedAuthority>();
authorities.add(new SimpleGrantedAuthority(user.getUserType()));
UsernamePasswordAuthenticationToken token = 
      new UsernamePasswordAuthenticationToken(users, null, authorities);

如果您不这样做，您的提供者将返回一个未授予访问权限的授权对象