java - Java 游戏中的死代码与玩家

Question

我有一个游戏，两个玩家轮流猜一个随机生成的数字。我正在使用如下方法来控制玩家转弯:

import java.util.Random;
import javax.swing.JOptionPane;

public class randomnumgame {

private static final int player1lives = 4;
private static final int player2lives = 4;
public static void main(String []args){
    while( player1lives > 0  &&  player2lives > 0){
        playerturn1();
        playerturn2();
    if (player1lives == 0 || player2lives == 0){
        game();
    }
}
}
public static void playerturn2() {
    int lives = player2lives;
    Random rand = new Random();
    int random = rand.nextInt(250) + 1;
    String player2 = JOptionPane.showInputDialog
        ("Please enter a number between 1 and 250, Player 2.");
    int player2int = Integer.parseInt(player2);
    if(player2int == random){
        JOptionPane.showMessageDialog(null, "Player 2 has guessed correctly. You have " +lives+ " lives left");
    }
    lives--;
    JOptionPane.showMessageDialog(null, "Your guess was wrong. The actual number was: " +random+ " You have " +lives+ " left" );
    }       
public static void playerturn1() {
    int lives = player1lives;
    Random rand = new Random();
    int random = rand.nextInt(250) + 1;
    String player1 = JOptionPane.showInputDialog
        ("Please enter a number between 1 and 250, Player 1.");
    int player1int = Integer.parseInt(player1);
    if(player1int == random){
        JOptionPane.showMessageDialog(null, "Player 1 has guessed correctly. You have " +lives+ " lives left");
    }
    lives--;
    JOptionPane.showMessageDialog(null, "Your guess was wrong. The actual number was: " +random+ " You have " +lives+ " lives left");
    }
private static void game(){
    if(player1lives == 0){
        JOptionPane.showMessageDialog(null, "Player 2 has won the game.");
        System.exit(0);
    }
    if(player2lives == 0 ){
        JOptionPane.showMessageDialog(null, "Player 1 has won the game.");
        System.exit(0);
    }
}
} 

问题是这段代码在 Eclipse 中被标记为无效代码:

    if (player1lives == 0 || player2lives == 0){
    game();
}

和:

  private static void game(){
    if(player1lives == 0){
        JOptionPane.showMessageDialog(null, "Player 2 has won the game.");
        System.exit(0);
    }
    if(player2lives == 0 ){
        JOptionPane.showMessageDialog(null, "Player 1 has won the game.");
        System.exit(0);
    }

我发现了类似的问题，但无法将它们应用到这个特定的应用程序中。任何帮助将不胜感激。

Answer 1

player1lives 和 player2lives 是final，因此永远无法更改。它们被设置为 value = 4，这意味着它们永远不会等于 0。

这里:

int lives = player2lives;
lives--;

你正在改变生命值。它不会影响 player2lives 值。

您应该将声明更改为:

private static int player1lives = 4;

然后就不需要 lives 变量了:

player1lives--;