mysql - Bash for 循环 : Backticks

Question

我有这个代码

$db=test-1
for T in `mysql -u$dbUser -p$dbPass -N -B -e 'show tables from '$db`;
do
count=$((count+1))
mysqldump --skip-comments --compact --skip-lock-tables -u$dbUser -p$dbPass $db $T > $GIT_MYSQL/$T.sql
done
done;

它给了我这个错误

ERROR 1064 (42000) at line 1: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '-1' at line 1

如何解决？

Answer 1

您没有正确声明数据库名称变量。尝试这样做:

$db=test-1
echo "My database is called $db"

将输出与此进行比较:

db=test-1
echo "My database is called $db"

考虑到上面的评论和正确的(我希望)引用，你的脚本应该可以工作:

dbUser="user"
dbPass="pass"
db="test-1"
for T in $(mysql -u "$dbUser" -p"$dbPass" -N -B -e "show tables from $db")
do
    mysqldump --skip-comments --compact --skip-lock-tables -u "$dbUser" -p"$dbPass" "$db" "$T" > "$GIT_MYSQL/$T.sql"
done