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php - MySQL JOIN 将 PHP 变量传递给两个表

转载 作者:行者123 更新时间:2023-11-29 07:16:59 27 4
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我在 PHP 中有以下 MySQL 查询,它传递一个变量来完成查询:

SELECT * from mobile_tech WHERE uid=$uid  order by timestamp DESC limit 0,1

我有以下 MySQL JOIN,它提供来自两个表的数据:

SELECT mobile_tech.latitude, mobile_tech.longitude, mobile_tech.timestamp, mobile_tech.uid, gbl_qemplisting.EmpNo, gbl_qemplisting.FirstName, gbl_qemplisting.LastName 
FROM mobile_tech, gbl_qemplisting
WHERE mobile_tech.uid=gbl_qemplisting.EmpNo AND date(timestamp)='$currentday'
group by uid

我需要使用 JOIN 将这两个查询合并为一个,并仍然传递 $uid 变量来完成查询。

我尝试了以下方法,但没有成功:

SELECT mobile_tech.latitude, mobile_tech.longitude, mobile_tech.timestamp, mobile_tech.uid, gbl_qemplisting.EmpNo, gbl_qemplisting.FirstName, gbl_qemplisting.LastName 
FROM mobile_tech, gbl_qemplisting
WHERE mobile_tech.uid=$uid AND gbl_qemplisting.EmpNo=$uid AND date(timestamp)='$currentday'

最佳答案

您的查询将返回 $uidmobile_techgbl_emplisting 行之间的叉积。如果您只需要一行(如第一个查询中所示),请类似地使用 ORDER BYLIMIT

SELECT mobile_tech.latitude, mobile_tech.longitude, mobile_tech.timestamp, mobile_tech.uid, gbl_qemplisting.EmpNo, gbl_qemplisting.FirstName, gbl_qemplisting.LastName 
FROM mobile_tech, gbl_qemplisting
WHERE mobile_tech.uid=$uid AND gbl_qemplisting.EmpNo=$uid AND date(timestamp)='$currentday'
ORDER BY mobile_tech.timestamp
LIMIT 1

关于php - MySQL JOIN 将 PHP 变量传递给两个表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37621596/

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