php - 如果行状态为 1 个使用 CodeIgniter 在 View 上批准的输出

Question

如果表行列状态为1，我想输出您已批准的语句。能够从数据库输出数据。现在我只想输出语句。

我的 Controller

public function index(){

    $this->load->database();  
    $this->load->model('Truckeraccount_model');  
    $data['account_details']=$this->Truckeraccount_model->account_details(); 
    $this->load->view('header'); 
    $this->load->view('truckers/truckeraccount_view', $data);  
    $this->load->view('footer'); 

}

我的模型

public function account_details() { 

    $this->db->select('*');
    $this->db->from('trucker');          
    $query = $this->db->get('trucker');      
    return $query;

}  

我的观点

  <?php
        foreach ($account_details->result() as $row)  
  {
  ?>   
            Area - <?php  echo $row->area;?><br>
            Mobile Number - <?php  echo $row->phone_number;?><br>
            Address - <?php  echo $row->address;?><br>
            Email Address - <?php  echo $row->email_address;?><br>
            Status - <?php  echo $row->status;?><br>

 <?php } ?>

Answer 1

使用这样的if语句，

<?php
    foreach ($account_details->result() as $row)  
     {
     ?>   
        Area - <?php  echo $row->area;?><br>
        Mobile Number - <?php  echo $row->phone_number;?><br>
        Address - <?php  echo $row->address;?><br>
        Email Address - <?php  echo $row->email_address;?><br>
        Status - <?php  if($row->status == 1) { echo 'you are Approved'; }?><br>

    <?php } ?>