Java - 使用递归查找单词的排列？

Question

我有一个程序，它会找到作为命令行参数给出的单词的所有可能排列，但无法从程序中获得任何输出，程序编译正常，当我运行程序时，我看不出有什么问题。有任何想法吗？

    import java.io.*;
02   
03  public class Anagrams
04  {
05      private static char [] word;
06      private static char [] permutation;
07      private static boolean [] characterUsed;
08   
09       
10       
11      public static void main(String [] args)throws Exception
12      {
13        
14         word = args[0].toCharArray();
15         permutation = new char[word.length];
16         characterUsed =  new boolean[word.length];
17         printPermutations(0);
18      }//main
19       
20     private static void printPermutations(int currentIndex)throws Exception          
02     {
03   
04      if(currentIndex == permutation.length)
05          System.out.println(permutation);
06      else
07      {
08          for(int index=0;index<word.length-1;index++)
09          {
10  //if the character at that index hasn't been used       
11             if(!characterUsed[index]);
12              {
13                 //mark character at this position as in use
14                 characterUsed[index] = true;
15                 //put the character in the permutation
16                permutation[index]= word[currentIndex];
17                 printPermutations(currentIndex +1);
18                 characterUsed[index] = false;
19               }//if
20           }//for
21         }//else
22       }//printPermutation
41  }//Anagrams

Answer 1

不确定这是否是唯一的问题，但这行看起来也有问题:

for (int index = 0; index < argument.length - 1; index++)

您的意思是不使用数组中的最后一个 char 吗？你可能是说:

for (int index = 0; index <= argument.length - 1; index++)

或

for (int index = 0; index < argument.length; index++)