java - 如何要求多个输入并在用户输入 0 时停止？

Question

我的程序应该接收大量的钱，并将其转换为零钱，但是当它接收到 0 时，它应该停止请求输入并停止程序。

我所有的数学都正确，我只是在重复询问数字时遇到问题。这是我目前拥有的:

public class Coins {

    public static int quarters;
public static int dimes;
public static int nickels;
public static int pennies;

    public static int Quarters(int TotalCoins) {
        quarters = (int) (TotalCoins / 25);
        TotalCoins %= 25;
        return quarters;
    }
    public static int Dimes(int TotalCoins){
        TotalCoins -= (quarters * 25);
        dimes = (int) (TotalCoins / 10);
        TotalCoins %= 10;
        return dimes;
}
    public static int Nickels(int TotalCoins){
        TotalCoins -= (dimes * 10) + (quarters * 25);
        nickels = (int) (TotalCoins / 5);
        TotalCoins %= 5;
        return nickels;
    }
    public static int Pennies(int TotalCoins){
        TotalCoins -= (nickels * 5 ) + (dimes * 10 ) + (quarters * 25);
        pennies = (int) (TotalCoins / 1);
        TotalCoins %= 1;
        return pennies;
    }
}

这是我的测试类(我很确定我的主要问题是):

public class CoinsTester {
    public static void main(String[] args) {           
        Scanner kybd = new Scanner(System.in);

        if (kybd.nextInt() != 0){
            int changeMoney = kybd.nextInt();
            System.out.println("Quarters = " + Coins.Quarters(changeMoney) + "\nDimes = " + Coins.Dimes(changeMoney) + "\nNickels = " + Coins.Nickels(changeMoney) + "\nPennies = " + Coins.Pennies(changeMoney));              
        }
    }
}

任何帮助都会很棒。

编辑:有人告诉我，在一节课中完成所有事情可能会更容易，如果是这样，那么以这种方式进行的任何建议也将非常出色。谢谢你!!!
编辑:我忘了提到我应该能够输入所有数字然后显示所有数字的输出。

Answer 1

你想要这样的东西:

Scanner kybd = new Scanner(System.in);

while (true) { 
    int changeMoney = kybd.nextInt();
    if (changeMoney == 0)
        break;

    // do stuff with changeMoney
}

也可以表示为一个for循环:

Scanner kybd = new Scanner(System.in);
for (int changeMoney = kybd.nextInt(); changeMoney != 0; changeMoney = kybd.nextInt()) {
    // do stuff with changeMoney 
}

虽然行数较少，但它使 for 循环行相当长，但可以通过使用较短的变量名来缓解这一问题:

Scanner in = new Scanner(System.in);
for (int i = in.nextInt(); i != 0; i = in.nextInt()) {
    // do stuff with i
}