java - 分别分析字符串的每个单词

Question

当我试图分别分析一个字符串的每个单词时，第一个单词做得很好，但其余的我都失败了。帮助我更正此 JAVA 代码以获得正确的输出:

public class Test {

 public static void main(String[] args) {


            int count1=0;
    int chars_not_x=0 ;

String str = "xyz xyxzghz zyxzz";
    String[] words = str.split("\\s");

for(int m=0; m<words.length; m++){

            System.out.println(words[m]);

            System.out.println("Total characters in the word: "+words[m].length());
    for(int n=0; n<words[m].length(); n++){
if(words[m].charAt(n)=='x'){count1++;}}

           System.out.println("Number of x :"+count1);
           chars_not_x= words[m].length()- count1; 
           System.out.println("Chars other than x: "+chars_not_x);

           System.out.println("\n");


  }} }

代码的输出是"

xyz
Total characters in the word: 3
Number of x :1
Chars other than x: 2


xyxzghz
Total characters in the word: 7
Number of x :3
Chars other than x: 4


zyxzz
Total characters in the word: 5
Number of x :4
Chars other than x: 1

所需的输出:

xyz
Total characters in the word: 3
Number of x :1
Chars other than x: 2


xyxzghz
Total characters in the word: 7
Number of x :2
Chars other than x: 5


zyxzz
Total characters in the word: 5
Number of x :1
Chars other than x: 4

Answer 1

根据需要工作代码-->

public class Test {
public static void main(String[] args) {

int count1=0;
int chars_not_x=0 ;

String str = "xyz xyxzghz zyxzz";
String[] words = str.split("\\s");

for(int m=0; m<words.length; m++){

count1 = 0;    // Add this

System.out.println(words[m]);

System.out.println("Total characters in the word: "+words[m].length());
for(int n=0; n<words[m].length(); n++){
if(words[m].charAt(n)=='x'){count1++;}}

       System.out.println("Number of x :"+count1);
       chars_not_x= words[m].length()- count1; 
       System.out.println("Chars other than x: "+chars_not_x);
       System.out.println("\n");


}} }