php - 在回显之前编辑字符串中的 url？

Question

不确定如何完成，但如何在回显来自数据库的结果之前编辑字符串中的 url？

基本上:

来自数据库的字符串:

Hello, I am Terry. I like using <a href="http://www.twitter.com">Twitter</a>, but I prefer using <a href="http://www.facebook.com">Facebook</a>. I like posting blogs on my website at <a href="http://www.mycoolsite.com">My Cool Site</a>, and I enjoying playing sports.

但我想回显:

Hello, I am Terry. I like using <a href="http://www.somepage.com/home?url=http://www.twitter.com">Twitter</a>, but I prefer using <a href="http://www.somepage.com/home?url=http://www.facebook.com">Facebook</a>. I like posting blogs on my website at <a href="http://www.somepage.com/home?url=http://www.mycoolsite.com">My Cool Site</a>, and I enjoying playing sports.

例如:替换 http://www.twitter.com在 href 中带有 http://www.somepage.com/home?url=http://www.twitter.com

Answer 1

这才是你真正要找的，

<?php   /** PHP, JavaScript and HTML/CSS mixed-code sample */

$string = 'Hello, I am Terry. I like using <a href="http://www.twitter.com">Twitter</a>, but I prefer using <a href="http://www.facebook.com">Facebook</a>. I like posting blogs on my website at <a href="http://www.mycoolsite.com">My Cool Site</a>, and I enjoying playing sports.';    
$myurl = "http://www.somepage.com/home?url=";

$result = preg_replace('/(<a[^>]*href[\s]*=["|\'])(.*?["|\'])/', "$1$myurl$2", $string);

echo $result;
?>

您可以在 phpfiddle.org 上尝试该代码，它正在运行。如果您需要任何更改，请告诉我。

更新代码:

<?php
$string = 'Hello, I am Terry. I like using <a href="http://www.twitter.com">Twitter</a>, but I prefer using <a href="http://www.facebook.com">Facebook</a>. I like posting blogs on my website at <a href="http://www.mycoolsite.com">My Cool Site</a>, and I enjoying playing sports.';
$myurl = "http://www.somepage.com/home?url=";

preg_match_all('/(<a[^>]*href[\s]*=)["|\'](.*?)["|\']/', $string, $result, PREG_SET_ORDER);

for($i=0;$i<count($result);$i++){
    $string = str_replace($result[$i][0], $result[$i][1] .'"'. $myurl . urlencode($result[$i][2]) .'"'  ,$string);
}

?>
<!--<textarea><?php echo $string; ?></textarea>-->
<?php echo $string; ?>