mysql - 违反完整性约束 : 1052 Column and in where clause is ambiguous

Question

我有两个表，Tbl_payroll_leave_employeev2 和 tbl_payroll_leave_schedulev2，我想加入它们，但我收到这样的错误

SQLSTATE[23000]: Integrity constraint violation: 1052 Column 'payroll_leave_employee_id' in where clause is ambiguous (SQL: select payroll_employee_id from tbl_payroll_leave_employee_v2 inner join tbl_payroll_leave_schedulev2 on tbl_payroll_leave_employee_v2.payroll_leave_employee_id = tbl_payroll_leave_schedulev2.payroll_leave_employee_id where payroll_leave_employee_id = 5) ◀

我的表结构

$employee_id = Tbl_payroll_leave_employeev2::select('payroll_employee_id')
   ->join('tbl_payroll_leave_schedulev2','tbl_payroll_leave_employee_v2.payroll_leave_employee_id','=','tbl_payroll_leave_schedulev2.payroll_leave_employee_id')
   ->where('payroll_leave_employee_id',$emp)
   ->get();

Answer 1

在where条件下，必须定义表tbl_payroll_leave_employee_v2或表tbl_payroll_leave_schedulev2的字段payroll_leave_employee_id

$employee_id = Tbl_payroll_leave_employeev2::select('payroll_employee_id')
   ->join('tbl_payroll_leave_schedulev2','tbl_payroll_leave_employee_v2.payroll_leave_employee_id','=','tbl_payroll_leave_schedulev2.payroll_leave_employee_id')
   ->where('tbl_payroll_leave_schedulev2.payroll_leave_employee_id',$emp)
   ->get();