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我使用DES 算法来加密/解密我的文本。它与拉丁文本完美搭配。
但是当我开始加密/解密西里尔文本时,解密的文本显示为 ?????? ???????? 在我的 TextField
表单和控制台中。我该如何解决?
在 Joachim Sauer advice 之后我将 inputBytes = textToEnrypt.getBytes();
更改为 inputBytes = textToEnrypt.getBytes("UTF-8");
现在我有 javax.crypto.IllegalBlockSizeException 。请帮助我...
package crypting;
import javax.crypto.Cipher;
import javax.crypto.spec.SecretKeySpec;
import javax.microedition.midlet.*;
public class Encryptor extends MIDlet {
String buffer;
public void startApp() {
String keyString = "testtest";
// encrypt("Text for encrypting", keyString);
encrypt("Привет", keyString);
decrypt(buffer, keyString);
}
public void pauseApp() {
}
public void destroyApp(boolean unconditional) {
}
public void encrypt(String textToEnrypt, String keyString) {
Cipher cipher;
try {
cipher = Cipher.getInstance("DES");
} catch (Exception ex) {
System.out.println(ex.toString());
return;
}
byte[] keyData = keyString.getBytes();
SecretKeySpec key = new SecretKeySpec(keyData, 0, keyData.length, "DES");
try {
cipher.init(Cipher.ENCRYPT_MODE, key);
} catch (Exception ex) {
System.out.println(ex.toString());
return;
}
int cypheredBytes = 0;
byte[] inputBytes;
try {
inputBytes = textToEnrypt.getBytes("UTF-8");
// inputBytes = textToEnrypt.getBytes();
} catch (Exception ex) {
System.out.println(ex.toString());
return;
}
byte[] outputBytes = new byte[100];
try {
cypheredBytes = cipher.doFinal(inputBytes, 0, inputBytes.length,
outputBytes, 0);
} catch (Exception ex) {
System.out.println(ex.toString());
return;
}
String str = new String(outputBytes, 0, cypheredBytes);
buffer = str;
System.out.println("Encrypted string = " + str);
}
public void decrypt(String textToDecrypt, String keyString) {
Cipher cipher;
try {
cipher = Cipher.getInstance("DES");
} catch (Exception ex) {
System.out.println(ex.toString());
return;
}
byte[] keyData = keyString.getBytes();
SecretKeySpec key = new SecretKeySpec(keyData, 0, keyData.length, "DES");
try {
cipher.init(Cipher.DECRYPT_MODE, key);
} catch (Exception ex) {
System.out.println("2. " + ex.toString());
return;
}
int cypheredBytes = 0;
byte[] inputBytes;
try {
inputBytes = textToDecrypt.getBytes("UTF-8");
// inputBytes = textToDecrypt.getBytes();
} catch (Exception ex) {
System.out.println("3. " + ex.toString());
return;
}
byte[] outputBytes = new byte[100];
try {
cypheredBytes = cipher.doFinal(inputBytes, 0, inputBytes.length,
outputBytes, 0);
} catch (Exception ex) {
System.out.println("4. " + ex.toString());
return;
}
String str = new String(outputBytes, 0, cypheredBytes);
System.out.println("Decrypted string = " + str);
}
}
最佳答案
我能够通过以下更改使其工作。
改变encrypt方法的返回类型,从void
到byte[]
:
static public byte[] encrypt(String textToEnrypt, String keyString)
throws Exception
{
//at the end
//write this down:
byte[] newResponse = new byte[cypheredBytes];
for(int i=0;i < cypheredBytes;i++)
{
newResponse[i] = outputBytes[i];
}
return newResponse;
}
代替:
String str = new String(outputBytes, 0, cypheredBytes);
buffer = str;
System.out.println("Encrypted string = " + str);
关于java - J2ME 文本加密 - javax.crypto.IllegalBlockSizeException,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/4896175/
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