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mysql - 从员工错误中选择 employee_name, count(dependent) as dependents

转载 作者:行者123 更新时间:2023-11-29 06:43:09 26 4
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我有这两个表“员工表,从属表”

员工表有“ID, employee_id, employee_name”

从属表有“ID, employee_id, dependent_name, relationship”

员工表的值为("1, 123, Vincent")

从属表的值为

("1, 123, Angel, daughter"),("2, 123, Mary, daughter")

我将如何显示 employee_id 和 employee_name 及其家属人数?

喜欢选择 employee_id, employee_name , count(dependent) as dependents ???

最佳答案

试试这个查询:

 select e.employee_id,e.employee_name,count(d.employee_id) as dependents
from department d
inner join employee e on (e.employee_id=d.employee_id)
group by d.employee_id;

Sql Fiddle Example

关于mysql - 从员工错误中选择 employee_name, count(dependent) as dependents,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20186120/

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