php - 在 PHP 中组合多个 MySQL 表的更好方法？

Question

我正在开发一个系统，为所有访问我的网站的用户生成一个 ID。如果用户创建帐户、申请信贷、购买产品...等等，它会将用户信息与数据库上的多个表中的此 ID 链接起来。我的问题是，合并所有信息需要很长时间，因为截至目前我们拥有超过 60,000,000 条记录。我之前创建的 VIEW 完全浪费了性能时间(最多需要 3 分钟)，因此我决定创建一个查询来获取数据并将非空字段与 PHP 结合起来，总共得到了 10-15 个结果秒也使用分页。如果可能的话，我希望它能够进一步改进。有什么建议吗？

    SELECT DISTINCT
    u.user_id,
    u.operating_system_name AS os,
    u.browser_name AS browser,
    u.ip_address,
    u.hardware_type AS hardware,
    u.city AS city,
    u.state AS state,
    u.country AS country,
    u.date AS date,

    m.id_member AS member,
    s.id_supplier AS supplier,
    c.id_entry AS credit,
    p.id_partner AS partner,
    cu.employee_ID AS careersus,
    cm.empleado_ID AS careersmx,
    o.id_order     AS orderid,

    o.recipient_name AS fn_o,
    m.first_name AS fn_m,
    c.first_name AS fn_c,
    p.first_name AS fn_p,
    s.contact_first_name AS fn_s,
    cu.firstname AS fn_cu,
    cm.nombre AS fn_cm,

    o.last_name AS ln_o,
    m.last_name AS ln_m,
    c.last_name AS ln_c,
    p.last_name AS ln_p,
    s.contact_last_name AS ln_s,
    cu.lastname AS ln_cu,
    cm.apellido AS ln_cm

    FROM tb_users_ids AS u 
    LEFT JOIN tb_orders AS o ON u.user_id = o.user_id
    LEFT JOIN tb_members AS m ON u.user_id = m.user_id
    LEFT JOIN financing AS c ON c.user_id = u.user_id
    LEFT JOIN tb_partners AS p ON p.user_id = u.user_id
    LEFT JOIN suppliers AS s ON s.user_id = u.user_id
    LEFT JOIN tb_careers_us AS cu ON cu.user_id = u.user_id
    LEFT JOIN tb_careers_mx AS cm ON cm.user_id = u.user_id
    WHERE u.user_id<>''
    ORDER BY u.date DESC
    LIMIT ".$offset.", ".$rowsperpage;

Answer 1

您必须为要比较的所有字段创建索引。因此，如果您的查询类似于 table1.user_id = table2.user_id ，请在 table1 和 table2 中为 user_id 定义索引。在所有 table 上都这样做。

然后它会非常非常快。