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我正在为我的实习以及我们在休息时玩的游戏制作记分牌。我有一个非常大的查询来获取所有游戏的结果并计算玩家获胜的总数。
SELECT winner, SUM(total) AS total
FROM (SELECT pw.name AS `winner`, COUNT(*) AS total
FROM billiard_games g
INNER JOIN players p1
ON p1.id = g.player_1
INNER JOIN players p2
ON p2.id = g.player_2
LEFT JOIN billiard_winners w
ON w.id = g.id
LEFT JOIN players pw
ON pw.id = w.winner
WHERE winner IS NOT NULL
GROUP BY winner
UNION ALL
SELECT pw.name AS `winner`, COUNT(*) AS total
FROM dart_games g
INNER JOIN players p1
ON p1.id = g.player_1
INNER JOIN players p2
ON p2.id = g.player_2
LEFT JOIN dart_winners w
ON w.id = g.id
LEFT JOIN players pw
ON pw.id = w.winner
GROUP BY winner
UNION ALL
SELECT pw.name AS `winner`, COUNT(*) AS total
FROM fifa_games g
INNER JOIN players p1
ON p1.id = g.player_1
INNER JOIN players p2
ON p2.id = g.player_2
LEFT JOIN fifa_winners w
ON w.id = g.id
LEFT JOIN players pw
ON pw.id = w.winner
WHERE winner IS NOT NULL
GROUP BY winner ) A
WHERE winner IS NOT NULL
group by winner DESC
LIMIT 5
输出:
Player_1 | 5
Player_2 | 1
Player_3 | 3
这不是正确的顺序。有什么问题吗?
最佳答案
最后一部分应该是
WHERE winner IS NOT NULL group by winner order by total DESC LIMIT 5
因为您刚刚错过了ORDER BY
关于php - 降序在查询中不起作用,但它应该起作用?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55101431/
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我尝试根据给定的级别顺序(BFS 顺序)构造 BST。我知道这是可能的,但我不知道我该怎么写。问题是我必须使用 BFS 序列。所以,我不能在这里使用递归,我必须迭代地编写我的程序......我发现这有
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