php - 令人困惑的mysql问题

Question

我有两个表的问题:

 CREATE TABLE IF NOT EXISTS `addresses` ( 
  `adr_id` int(11) NOT NULL auto_increment, 
  `per_id` int(11) NOT NULL, 
  `adr_street` varchar(50) NOT NULL, 
  `adr_houseno` int(11) default NULL, 
  `adr_housenoadd` varchar(10) default NULL, 
  `adr_postalcode` varchar(25) NOT NULL, 
  `adr_city` varchar(20) NOT NULL, 
  `adr_type` varchar(45) default NULL, 
  `cnt_id` int(11) NOT NULL, 
  `adr_date` date default NULL, 
  `sys-mut-dt` timestamp NULL default NULL, 
  `sys-mut-user` varchar(20) default NULL, 
  `sys-mut-id` int(11) NOT NULL default '0', 
  PRIMARY KEY  (`adr_id`), 
  KEY `per_id` (`per_id`), 
  KEY `cnt_id` (`cnt_id`) 
) ENGINE=InnoDB DEFAULT CHARSET=utf8 ; 
-- 
-- RELATIES VOOR TABEL `addresses`: 
--   `cnt_id` 
--       `countries` -> `cnt_id` 
--   `per_id` 
--       `persons` -> `per_id` 
-- 

CREATE TABLE `events` ( 
  `evt_id` int(11) NOT NULL auto_increment, 
  `evt_name` varchar(50) NOT NULL, 
  `evt_description` varchar(100) default NULL, 
  `evt_startdate` date NOT NULL, 
  `evt_enddate` date default NULL, 
  `evt_starttime` time default NULL, 
  `evt_endtime` time default NULL, 
  `evt_amtpersons` int(11) default NULL, 
  `sts_id` int(11) NOT NULL, 
  `adr_id` int(11) default NULL, 
  `evt_amtPersonsSubs` tinyint(4) NOT NULL default '0', 
  `evt_photo` varchar(50) default NULL, 
  `sys-mut-dt` timestamp NULL default CURRENT_TIMESTAMP on update CURRENT_TIMESTAMP, 
  `sys-mut-user` varchar(20) default NULL, 
  `sys-mut-id` int(11) NOT NULL default '0', 
  PRIMARY KEY  (`evt_id`), 
  KEY `sts_id` (`sts_id`), 
  KEY `adr_id` (`adr_id`) 
) ENGINE=InnoDB DEFAULT CHARSET=utf8; 

问题是，当我尝试从地址表中删除记录时，出现以下错误

DELETE
FROM    addresses
WHERE   per_id = 45

1451 - Cannot delete or update a parent row: a foreign key constraint fails (`site/events`, CONSTRAINT `adr_id` FOREIGN KEY (`adr_id`) REFERENCES `addresses` (`adr_id`) ON DELETE NO ACTION ON UPDATE NO ACTION) ; 

奇怪的是，events表中没有相同per_id或adr_id的记录。

那么这里发生了什么？

我该如何解决这个问题？ ;-)

/* I think it means "How can I solve this?" */

Answer 1

这可能听起来很愚蠢，但是您绝对确定没有子行吗？

您能运行一下吗:

SELECT  e.*
FROM    addresses a
JOIN    events e
ON      e.adr_id = a.adr_id
WHERE   a.per_id = 45