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Php - 通知 : Undefined offset 10?

转载 作者:行者123 更新时间:2023-11-29 06:19:33 26 4
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<分区>

<?php

require "connection.php";

$cek = mysql_query("SELECT * FROM `kelimeler` ORDER BY `numara` DESC LIMIT 10");

$i = 0;
$tr_dizi = array();
$alm_dizi = array();

while ($satir = mysql_fetch_array($cek)) {
$tr_dizi[$i] = $satir["turkce"];
$alm_dizi[$i] = $satir["almanca"];
$i++;
}

$deger = rand(1,10);

setcookie("soru", $tr_dizi[$deger]);
setcookie("cevap", $alm_dizi[$deger]);

?>

<?php

if (isset($_POST["kelime"])) {
if ($_POST["kelime"] == $_COOKIE['cevap']) {
echo '<div class="bildirim">Richtig &#10004</div>';
} else {
echo '<div class="bildirim">'.$_COOKIE['soru'].' = '.$_COOKIE['cevap'].'</div>';
}
}

?>

这是一个类似于 a = b 的问答游戏,a 是什么?如果用户发送 b 它说“是!”否则正确答案是 'b' php say

Notice: Undefined offset: 10 on line 19 - 20 - 55

Line 19 -> setcookie("soru", $tr_dizi[$deger]);  
Line 20 -> setcookie("cevap", $alm_dizi[$deger]);
Line 55 -> <divclass="kelime"><?php echo $tr_dizi[$deger] ?></div>

when user send the answer program check it and ask new question and yes or no is showing on new page i'm using cookies for that

我该如何修复这个错误我可以进行错误处理但我是一个新开发人员我想学习谢谢大家:)

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