java - ReSTLet 教程示例

Question

我在获取 tutorial 时遇到问题在 GAE 上工作的示例。 AppEngine 日志说:

"GET /contacts/123 HTTP/1.1" 404 598 - "Restlet-Framework/2.1snapshot,gzip(gfe)"
javax.servlet.ServletContext log: ContactRestlet: [Restlet] Attaching application: com.sem.server.rest.ContactApp@1bbc779 to URI: /contacts/123
This request caused a new process to be started for your application, and thus caused your application code to be loaded for the first time. This request may thus take longer and use more CPU than a typical request for your application.

我无法从我的 android 客户端或浏览器访问它。感谢您的帮助!

web.xml如下

<web-app xmlns="http://java.sun.com/xml/ns/javaee" version="2.5">

<context-param>
    <param-name>org.restlet.clients</param-name>
    <param-value>CLAP FILE</param-value>
  </context-param>  

<servlet>
  <servlet-name>PoiServiceImpl</servlet-name>
  <servlet-class>com.sem.server.PoiServiceImpl</servlet-class>
</servlet>

<servlet>
   <servlet-name>PoiRestlet</servlet-name>
   <servlet-class>org.restlet.ext.servlet.ServerServlet</servlet-class>
      <init-param>
        <param-name>org.restlet.application</param-name>
        <param-value>com.sem.server.rest.PoiApp</param-value>
      </init-param>
</servlet>

<servlet>
   <servlet-name>ContactRestlet</servlet-name>
   <servlet-class>org.restlet.ext.servlet.ServerServlet</servlet-class>
      <init-param>
        <param-name>org.restlet.application</param-name>
        <param-value>com.sem.server.rest.ContactApp</param-value>
      </init-param>
</servlet>

<servlet>
   <servlet-name>CatRestlet</servlet-name>
   <servlet-class>org.restlet.ext.servlet.ServerServlet</servlet-class>
      <init-param>
        <param-name>org.restlet.application</param-name>
        <param-value>com.sem.server.rest.CatApp</param-value>
      </init-param>
</servlet>

<servlet-mapping>
  <servlet-name>PoiServiceImpl</servlet-name>
  <url-pattern>/sem10/PoiService</url-pattern>
</servlet-mapping>

<servlet-mapping>
    <servlet-name>PoiRestlet</servlet-name>
    <url-pattern>/poi</url-pattern>
</servlet-mapping>

<servlet-mapping>
    <servlet-name>ContactRestlet</servlet-name>
    <url-pattern>/contacts/123</url-pattern>
</servlet-mapping>

<servlet-mapping>
    <servlet-name>CatRestlet</servlet-name>
    <url-pattern>/cat</url-pattern>
</servlet-mapping>


  <!-- Default page to serve -->
  <welcome-file-list>
    <welcome-file>Sem10.html</welcome-file>
  </welcome-file-list>

</web-app>

联系应用

import java.io.File;    
import org.restlet.Application;
import org.restlet.Component;
import org.restlet.Restlet;
import org.restlet.data.LocalReference;
import org.restlet.data.Protocol;
import org.restlet.resource.Directory;
import org.restlet.routing.Router;

public class ContactApp extends Application {

/**
 * When launched as a standalone application.
 * 
 * @param args
 * @throws Exception
 */
public static void main(String[] args) throws Exception {
    Component component = new Component();
    component.getClients().add(Protocol.FILE);
    component.getServers().add(Protocol.HTTP, 8080);
    component.getDefaultHost().attach(new ContactApp());
    component.start();
}

@Override
public Restlet createInboundRoot() {
    Router router = new Router(getContext());
    getConnectorService().getClientProtocols().add(Protocol.FILE);

 // Serve the files generated by the GWT compilation step.
    File warDir = new File("");
    if (!"war".equals(warDir.getName())) {
        warDir = new File(warDir, "war/");
    }

    Directory dir = new Directory(getContext(), LocalReference
            .createFileReference(warDir));
    router.attachDefault(dir);


       router.attach("/contacts/123", ContactServResource.class);

        return router;
    }
}

Answer 1

Dev-Mailinglist 友善地回答了我的问题:

here