php - 数据库连接查询错误

Question

查看我的错误日志，我经常收到以下错误:

[01-Mar-2011 04:31:27] exception 'Exception' with message 'Query failed' in /home1/mexautos/public_html/kiubbo/data/model.php:89
Stack trace:
#0 /home1/mexautos/public_html/kiubbo/data/article.php(275): Model::execSQl2('update articles...')
#1 /home1/mexautos/public_html/kiubbo/data/article.php(111): Article->save()
#2 /home1/mexautos/public_html/kiubbo/pages/frontpage.php(21): Article->calculateRanking()
#3 /home1/mexautos/public_html/kiubbo/pages/frontpage.php(27): FrontPage->updateRanking()
#4 /home1/mexautos/public_html/kiubbo/index.php(15): FrontPage->showTopArticles('')
#5 {main}

如果我转到 model.php 文件，我会看到以下内容:

static function execSQl2($query)
    {
    /*
            Execute a SQL query on the database
            passing the tablename and the sql query.
            Returns the LAST_INSERT_ID
    */


        $db = null;
        $lastid = null;
        //echo "query is $query";

        try
        {
            $db = Model::getConnection();
            $results = $db->query($query);
            if(!$results) {
                throw new Exception('Query failed', EX_QUERY_FAILED );
            }
            $lastid = $db->insert_id;
        }
        catch(Exception $e)
        {
            /*  errors are handled higher in the
                    object hierarchy
            */

            throw $e;
        }

有人看到错误吗，或者我应该看看其他地方？

谢谢您并致以问候，卡洛斯

编辑:

这是查询:$lastid = Parent::execSql2($query);

这是上下文:

function save() {

    /*
            Here we do either a create or
            update operation depending
            on the value of the id field.
            Zero means create, non-zero
            update
    */

        if(!get_magic_quotes_gpc())
        {
            $this->title = addslashes($this->title);
            $this->description = addslashes($this->description);
        }

        try
        {
            $db = parent::getConnection();
            if($this->id == 0 )
            {
                $query = 'insert into articles (modified, username, url, title, description, points )';
                $query .= " values ('$this->getModified()', '$this->username', '$this->url', '$this->title', '$this->description', $this->points)";

            }
            else if($this->id != 0)
            {
                $query = "update articles set modified = NOW()".", username = '$this->username', url = '$this->url', title = '".$this->title."', description = '".$this->description."', points = $this->points, ranking = $this->ranking where id = $this->id";
            }

            $lastid = parent::execSql2($query);

            if($this->id == 0 )
                $this->id = $lastid;

        }
        catch(Exception $e){
            error_log($e);
        }
    }

问候，卡洛斯

Answer 1

正如 heximal 所说，这可能是您的 SQL 查询中的错误。将正在查询的完整 SQL 复制并粘贴到 PhpMyAdmin 或类似工具中，然后查看出现什么错误(如果有)。通常，问题只是表输入错误或值缺失。当然，如果您需要帮助，也可以在这里发布查询! :D