PHP/SQL Sum 客户总数

Question

由于不同的原因，我的数据库有重复项，我正在尝试获取每个用户 ID 的唯一客户总数。

这是我构建的当前查询。

    $ApprovedCustomerCount ="SELECT `".Customer_Full_Name."`, `".Customer_Address."`, COUNT(DISTINCT(`".Customer_Full_Name."`)) AS CustomersCount 
                            FROM `".OrdersTable."` 
                            WHERE `".Users_Sales_ID."`=$EMPID
                            AND `".Current_Order_Stage."`='".Current_Order_Stage_Approved."' 
                            GROUP BY `".Customer_Full_Name."`, `".Customer_Address."` 
                            HAVING COUNT(".Customer_Full_Name.") > 1";

    $ApprovedCustomerResult=mysql_query($ApprovedCustomerCount);
    while($OrdersRow=mysql_fetch_array($ApprovedCustomerResult))
    $CustomerApprovedCount = $OrdersRow['CustomersCount'];

    if (empty($CustomerApprovedCount)) { $CustomerApprovedCount = '0'; }    
echo $CustomerApprovedCount;

错误的是，当我在 PHP 中回显时，它只给我 1 的值。

但是，当我用确切的查询查询数据库表时，我得到一个输出(对于每个客户名称，唯一计数的地址 = 1)，它将显示客户列表，并给我 67。这就是我需要的数字。

在我运行的 PhpMyAdmin 中查询

SELECT `CustomerName`, `CustomerAddress`, COUNT(DISTINCT(`CustomerName`)) AS Customers 
FROM `wrightway_orders` 
WHERE `Employee_ID` = '3020'
AND `Order Stage`='Approved'
GROUP BY `CustomerName`, `CustomerAddress` 
HAVING COUNT(*) > 1 

输出

+------------------+----------------------+----------------+
|  Customer Name   |  Address             | CustomersCount |
+------------------+----------------------+----------------+
| ADRIANE JOHNSON  |  10015 161ST PL NE   |        1       |
+------------------+----------------------+----------------+
| BILL SMITH       |  9923 161ST AVE NE   |        1       |
+------------------+----------------------+----------------+
| BRIAN WALTERS    |  11129 106TH AVE NE  |        1       |
+------------------+----------------------+----------------+

等等

我需要对 定义为“CustomerCount” 值的 总数 求和，然后将该值回显为 echo $CustomerApprovedCount;

我哪里错了？

感谢您的帮助:)

我需要计算所有唯一的客户，然后给出 Employee_ID=ID# 的所有客户的总和。

Answer 1

只需使用 mysql_num_rows 结果:

$ApprovedCustomerResult = mysql_query($ApprovedCustomerCount);
$CustomerApprovedCount = mysql_num_rows($ApprovedCustomerResult);