PHP计算剩余时间

Question

我有一个函数

function getEndTimeRemaining($timestamp, $format) {       
    $difference = $timestamp - time();
    if($difference < 0)
        return false;
    else{

        $min_only = intval(floor($difference / 60));
        $hour_only = intval(floor($difference / 3600));

        $days = intval(floor($difference / 86400));
        $difference = $difference % 86400;
        $hours = intval(floor($difference / 3600));
        $difference = $difference % 3600;
        $minutes = intval(floor($difference / 60));
        if($minutes == 60){
            $hours = $hours+1;
            $minutes = 0;
        }

        if($days == 0){
            $format = str_replace('Days', '?', $format);
            $format = str_replace('Ds', '?', $format);
            $format = str_replace('%d', '', $format);
        }
        if($hours == 0){
            $format = str_replace('Hours', '?', $format);
            $format = str_replace('Hs', '?', $format);
            $format = str_replace('%h', '', $format);
        }
        if($minutes == 0){
            $format = str_replace('Minutes', '?', $format);
            $format = str_replace('Mins', '?', $format);
            $format = str_replace('Ms', '?', $format);       
            $format = str_replace('%m', '', $format);
        }

        $format = str_replace('?,', '', $format);
        $format = str_replace('?:', '', $format);
        $format = str_replace('?', '', $format);

        $timeLeft = str_replace('%d', number_format($days), $format);       
        $timeLeft = str_replace('%ho', number_format($hour_only), $timeLeft);
        $timeLeft = str_replace('%mo', number_format($min_only), $timeLeft);
        $timeLeft = str_replace('%h', number_format($hours), $timeLeft);
        $timeLeft = str_replace('%m', number_format($minutes), $timeLeft);

        if($days == 1){
            $timeLeft = str_replace('Days', 'Day', $timeLeft);
            $timeLeft = str_replace('Ds', 'D', $timeLeft);
        }
        if($hours == 1 || $hour_only == 1){
            $timeLeft = str_replace('Hours', 'Hour', $timeLeft);
            $timeLeft = str_replace('Hs', 'H', $timeLeft);
        }
        if($minutes == 1 || $min_only == 1){
            $timeLeft = str_replace('Minutes', 'Minute', $timeLeft);
            $timeLeft = str_replace('Mins', 'Min', $timeLeft);
            $timeLeft = str_replace('Ms', 'M', $timeLeft);           
        }

      return $timeLeft;
    }
}

我传入一个 MySQL 日期时间字段，该字段将转换为 strtotime

getEndTimeRemaining(strtotime($get_auction_details_result['end_date']), "%mo").

它将返回分钟数，即如果还剩 1 分钟则返回 1，如果只剩下几秒则返回 0，但我想知道还剩多少秒，即还剩 24 秒等。

谢谢

Answer 1

如果您使用 PHP >= 5.3，确实没有必要重新发明轮子

使用DateTime::diff() 。返回的 DateInterval 为您提供了您想要的所有部分，并且有自己的方法。