php - 显示函数中的数组内容？

Question

谁能告诉我如何显示下面代码中的 next 值？

在我的 user.php 文件中，我有以下内容:

class User {
    protected $userID;
    protected $useremail;
    protected $userPassword;
    public function __construct() {
        $this->userID = preg_replace('#[^0-9]#i', '', 
            $_SESSION['user_id']);
        $this->useremail = preg_replace('#[^A-Za-z0-9@_.-]#i', '', 
            $_SESSION['user']);
        $this->userPassword = preg_replace('#[^A-Za-z0-9]#i', '', 
            $_SESSION['user_password']);
    }

public function UserInfoQuery() {
    $sql = "SELECT * FROM users WHERE id = 
       '$this->userID' AND email = '$this->useremail' AND 
        password = '$this->userPassword' LIMIT 1";
    $res = mysql_query($sql) or die(mysql_error()); 
    $userMatch = mysql_numrows($res);

    if ($userMatch == 1) {
        while($row = mysql_fetch_array($res)) {
            $userData = array(
                $userFirstname = $row['firstName'],
                $userLastname = $row['lastName'],
                $userBirthdate = $row['birthDate'],
                $userSex = $row['sex'],
                $userEmail = $row['email'],
                $userCountry = $row['country'],
                $userRegion = $row['region']);
            }
        }

        return $userData;
    }
}

当我尝试时，在我的索引 php 文件中:

$User = new User();
print_r($User->UserInfoQuery());

我有下一个结果:

Array ( [0] => firstname [1] => 
    lastname [2] => 
    1990-11-23 [3] => 
    male [4] => 
    mail [5] => 
    Srbija [6] => town ) 

如何仅回显名字和姓氏？

Answer 1

这个:

array($userFirstname = $row['firstName'])

将 $row['firstName'] 的值赋给变量 $userFirstname，然后将赋值结果($row 的值['firstName']) 到一个数组中。与编写相同:

$userFirstname = $row['firstName'];
array($row['firstName']);

要使用 key userFirstname 声明一个数组，您需要编写:

array('userFirstname' => $row['firstName'])

从这里，您可以访问一个普通数组:

$userinfo = $User->UserInfoQuery();
echo $userinfo['userFirstname'];

这看起来确实有点笨拙，而且说实话，你在这里并没有很好地使用对象。您应该将从数据库查询到的数据保存到对象的属性中，然后使用 getter 来一一或全部访问这些属性。不过，如何设计一个合适的对象有点超出了这个答案的范围/要点。