Java midi 音符通过音符的 Octave 音程映射到字符串

Question

在我的项目中，我希望至少能够告知用户他们需要弹奏的音符在哪个弦上。我可以得到音符及其 Octave 音阶，但正如我发现的那样，该音符及其 Octave 音阶可以出现在吉他指板上的多个位置。

所以我的问题是:是否可以将 MIDI 音符映射到吉他弦？

Answer 1

以下代码获取 MIDI 音符值并返回吉他指板上最接近乐器末尾的位置。零品是空弦。

static class Fingering {
    int string;
    int fret;

    public String toString() {
        return "String : " + stringNames[string] + ", fret : " + fret;
    }
}

static String[] stringNames = new String[] {"Low E", "A", "D", "G", "B", "High E"}; 

    /** Array showing guitar string's relative pitches, in semi-tones, with "0" being low E */
static int[] strings = new int[]{64, 69, 74, 79, 83, 88};



public static Fingering getIdealFingering(int note) {
            if (note < strings[0])
                throw new RuntimeException("Note " + note + " is not playable on a guitar in standard tuning.");

    Fingering result = new Fingering();

    int idealString = 0;
    for (int x = 1; x < strings.length; x++) {
        if (note < strings[x])
            break;
        idealString = x; 
    }

    result.string = idealString;
    result.fret = note - strings[idealString];

    return result;
}

public static void main(String[] args) {
    System.out.println(getIdealFingering(64));  // Low E
    System.out.println(getIdealFingering(66));  // F#
    System.out.println(getIdealFingering(72));  // C on A string
    System.out.println(getIdealFingering(76));  // E on D string
    System.out.println(getIdealFingering(88));  // guitar's high e string, open
    System.out.println(getIdealFingering(100)); // high E, 12th fret
    System.out.println(getIdealFingering(103)); // high G
}

结果:

String : Low E, fret : 0
String : Low E, fret : 2
String : A, fret : 3
String : D, fret : 2
String : High E, fret : 0
String : High E, fret : 12
String : High E, fret : 15