ios - 使用 UISearchController Swift 4 搜索多个结构体数组

Question

我有两个数据数组，我想搜索它们，但不知道如何使用 UISearchController 搜索这两个数据

struct Fish {
   var name: String
   var price: Int
}
var fishArray: [Fish] = [   Fish(name: "Bass", price: 1),
                            Fish(name: "Pike", price: 2),
                            Fish(name: "Carp", price: 3),
                            Fish(name: "Bluegill", price: 4),
                            Fish(name: "Catfish", price: 5)]
struct Weapons {
   var name: String
   var price: Int
}
var weaponsArray: [Weapons] = [   Weapons(name: "Sword", price: 1),
                                  Weapons(name: "Knife", price: 2),
                                  Weapons(name: "Gun", price: 3),
                                  Weapons(name: "Poison", price: 4),
                                  Weapons(name: "Hammer", price: 5)]

搜索发生在这里。仅搜索武器效果很好，但稍后如何添加鱼和多个其他数组。

func filterContentForSearchText(_ searchText: String, scope: String = "All") {
    filteredData = weaponsArray.filter({( weapon : Weapons) -> Bool in
        return weapon.name.lowercased().contains(searchText.lowercased())
    })

    mainTableView.reloadData()
}

希望这对某人有意义!谢谢!

Answer 1

如果它们都有名称和价格，您可以执行类似的操作，对于最后一部分，您可以向上转换另一个数组并将它们组合成一个大数组:

protocol Item {
    var name: String { get set }
    var price: Int { get set }
}

struct Fish: Item {
    var name: String
    var price: Int
}
var fishArray: [Fish] = [   Fish(name: "Bass", price: 1),
                            Fish(name: "Pike", price: 2),
                            Fish(name: "Carp", price: 3),
                            Fish(name: "Bluegill", price: 4),
                            Fish(name: "Catfish", price: 5)]
struct Weapons: Item {
    var name: String
    var price: Int
}
var weaponsArray: [Weapons] = [   Weapons(name: "Sword", price: 1),
                                  Weapons(name: "Knife", price: 2),
                                  Weapons(name: "Gun", price: 3),
                                  Weapons(name: "Poison", price: 4),
                                  Weapons(name: "Hammer", price: 5)]

var items: [Item] = (fishArray as [Item]) + (weaponsArray as [Item])
items.filter { (item) -> Bool in
    return item.name.lowercased().contains("C".lowercased())
}