php - 错误的 bool 值语句未插入数据库

Question

我有一个如下所示的 JSON 数组:

{
    "operation": "update_original_team_member",
    "teamMember": {
        "teamMemberPresent": false,
        "unique_id": "5a5b7f6b835408.50059003",
        "user_unique_id": "59bea8b7d56a63.33388595"
    }
}

我试图将它插入到 mySQL 数据库中，但每次都失败，但是当我将 false 更改为 true 时，它​​起作用了，知道这是为什么吗？

插入的表如下:

CREATE TABLE team_member (
    team_member_id int(11) NOT NULL AUTO_INCREMENT,
    unique_id varchar(23) NOT NULL,
    fullName varchar(50) NOT NULL,
    user_unique_id varchar(23) NOT NULL,
    present boolean NOT NULL,
    date_last_present datetime DEFAULT NULL,
    points int(50) NULL,
    team_id int (11) NOT NULL,
     PRIMARY KEY (team_member_id),
     FOREIGN KEY (`team_id`)
    REFERENCES `ocidb_CB9s149919`.`team` (`team_id`)
    );

JSON 数组从 Retrofit 发送(Retrofit 是 Android 的 REST 客户端)并按如下方式接收:

if ($operation == 'update_original_team_member') {

            if (isset($data -> teamMember) && !empty($data -> teamMember)&& isset($data -> teamMember -> teamMemberPresent)
                && isset($data -> teamMember -> unique_id)&& isset($data -> teamMember -> user_unique_id)){

              $teamMember                 = $data             -> teamMember;
              $teamMemberPresent          = $teamMember       -> teamMemberPresent;
              $unique_id                  = $teamMember       -> unique_id;
              $user_unique_id             = $teamMember       -> user_unique_id;


              echo $fun -> updatePresent($teamMemberPresent,$unique_id, $user_unique_id);

              } else {


              echo $fun -> getMsgInvalidParam();

            }

这是传递给以下函数:

public function updatePresent($teamMemberPresent,$unique_id, $user_unique_id){

     $db = $this -> db;

     if (!empty ($teamMemberPresent)&& !empty ($unique_id)&& !empty ($user_unique_id)){

         $result = $db -> updatePresent($teamMemberPresent,$unique_id, $user_unique_id);

         if ($result) {

            $response["result"] = "success";
            $response["message"] = "Active Students Have Been Recorded!";
            return json_encode($response);

         } else {

            $response["result"] = "failure";
            $response["message"] = "Unable To Update Details, Please Try Again";
            return json_encode($response);

         }
         } else {

      return $this -> getMsgParamNotEmpty();

            }

}   

我用来更新的查询是:

public function updatePresent($teamMemberPresent,$unique_id, $user_unique_id){



$sql = "UPDATE team_member SET present = :present WHERE unique_id = :unique_id AND user_unique_id = :user_unique_id";


// Prepare statement
$query = $this ->conn ->prepare($sql);

// execute the query
$query->execute(array(':present' => $teamMemberPresent,':unique_id' => $unique_id, ':user_unique_id' => $user_unique_id));

if ($query) {

return true;        

} else {

return false;

    }
 }

我已经使用 postman 来尝试隔离问题，并将其缩小到 $teamMemberPresent 变量失败，声明它在 interting 为 false 时为空，但我没有知道为什么。正如我之前提到的，当它设置为 true 时，查询工作正常。

任何指导将不胜感激。

Answer 1

在您的 updatePresent() 函数中，此代码无法将数据识别为有效，并跳过数据库更新:

if (!empty ($teamMemberPresent)&& !empty ($unique_id)&& !empty ($user_unique_id)){
 ... 

原因是 empty($teamMemberPresent) 如果其参数具有 false 值，则返回 true。

http://php.net/empty说:

A variable is considered empty if it does not exist or if its value equals FALSE.

您应该改用 isset($teamMemberPresent)。

这是一个演示:

if (isset($data -> teamMember)
&& !empty($data -> teamMember)
&& isset($data -> teamMember -> teamMemberPresent)
&& isset($data -> teamMember -> unique_id)
&& isset($data -> teamMember -> user_unique_id))
{       
        echo "Should all be OK\n";  

        $teamMember                 = $data             -> teamMember;
        $teamMemberPresent          = $teamMember       -> teamMemberPresent;

        if (!empty($teamMemberPresent)) {
                echo "Confirmed, not empty\n";
        } else {
                echo "Woops! It's empty\n";
        }
}

输出:

Should all be OK
Woops! It's empty