MySQL : first day of the week and last day of the week not working as desired

Question

我有一个名为 stockins 的 table 和一个 column stock。因为我想在一周的第一天和一周的最后一天之间找到 max(stock)。

为此，我使用以下查询

select max(stock) 
from stockins 
where date >= '(DATE(NOW()) - INTERVAL (WEEKDAY(DATE(NOW()))) DAY)' 
and date <= '(DATE(NOW() + INTERVAL (6 - WEEKDAY(NOW())) DAY))'

但是输出出错了。

如果我运行下面的查询

select max(stock) 
from stockins 
where date >= '(DATE(NOW()) - INTERVAL (WEEKDAY(DATE(NOW()))) DAY)' 
and date <= '2018-01-28'

然后我得到了想要的输出。

我哪里可能出错了？

Answer 1

只需删除单引号。

select max(stock) from stockins where date >= (DATE(NOW()) - INTERVAL (WEEKDAY(DATE(NOW()))) DAY) and date <= (DATE(NOW() + INTERVAL (6 - WEEKDAY(NOW())) DAY))