java - 为什么 FindBugs 在这里提示？

Question

 public int getFreezeColumns() {
    Integer currentValue = (Integer) checkValueBinding("freezeColumns", this.freezeColumns);
    if (currentValue != null) {
      return currentValue;
    }
    return 0;
  }

FindBugs 说:

A primitive is boxed, and then immediately unboxed. This probably is due to a manual boxing in a place where an unboxed value is required, thus forcing the compiler to immediately undo the work of the boxing.

我该如何解决这个问题？

Answer 1

我认为投诉有些误导:您没有装箱 checkValueBinding 的返回值，它是一个 Object，而是将其转换为 Integer 过早地

尝试更改代码以查看它是否可以帮助您避免警告:

public int getFreezeColumns() {
    Object currentValue = checkValueBinding("freezeColumns", this.freezeColumns);
    if (currentValue != null) {
        return (Integer)currentValue;
    }
    return 0;
}