ios - 在哪里快速设置委托(delegate)？

Question

我已经建立了一个简单的 Swift 项目来尝试理解委托(delegate)和协议(protocol)。目标是在两个类(SendingClass 和 ReceivingClass)之间传递数据。 SendingClass 中的两个按钮链接到委托(delegate)，该委托(delegate)应触发 ReceivingClass 中的符合协议(protocol)的函数执行。不幸的是，这不起作用，我怀疑这与我将 ReceivingClass 声明为委托(delegate)的位置和方式有关。

感谢您的见解，我才刚刚开始!

我尝试在不同位置设置委托(delegate)(目前在 viewDidLoad 中，但无法使其工作)。

let vc = SendingClass()
vc.statusDelegate = self

SendingClass.swift

import UIKit


protocol StatusDelegate {
    func statusChanged(state: Bool, sender: String)
}

class SendingClass: UIViewController {

    var statusDelegate : StatusDelegate?


    @IBAction func button1Pressed(_ sender: UIButton) {
      statusDelegate?.statusChanged(state: true, sender: "Button 1")
    }

    @IBAction func button2Pressed(_ sender: UIButton) {
        statusDelegate?.statusChanged(state: false, sender: "Button 2")
    }

}

ReceivingClass.swift

import Foundation
import UIKit

class ReceivingClass: UIViewController, StatusDelegate {

    override func viewDidLoad() {
        let vc = SendingClass()
        vc.statusDelegate = self
    }

    func statusChanged(state: Bool, sender: String) {
        print("Sender = \(sender) , State = \(state)")
    }
}

预期:每次在 SendingClass 中按下按钮时，ReceivingClass 协议(protocol)符合函数 (func statusChanged) 应执行。

实际:什么也没发生

Answer 1

I am using this..
// create extension in your receiving class
extension ReceivingClass: PopUpVCDelegate {
   func statusChanged(state: Bool, sender: String) {
        print("Sender = \(sender) , State = \(state)")
    }
}

// on sending class, when you present your receiving class on any button click
eg.
let resultController = self.storyboard?.instantiateViewController(withIdentifier: "PopUpVCID") as? PopUpVC       

        resultController?.delegate = self
  self.present(resultController!, animated: true, completion: nil)

 //or if not have button add on viewdidload in receiving class

// here is full eg

How to get data from popup view controller to custom table view cell?