java - 在 java 1.6 中以优雅的方式切换字符串

Question

我使用的是 java 1.6，我知道从 java 1.7 开始可以选择打开字符串但在这里我使用 if/elseif 来路由类型名称，我的问题是是否有一种优雅的方式我可以将其更改为 switch Yet

public static SwitchType<?> switchT(final String typeName,
                                    final String memberName) {

    if (typeName.equals("java.lang.String")) {
        return new SwitchInputType<String>(new String(memberName + " "));

    } else if (typeName.equals("char")) {
        return new SwitchInputType<Character>(new Character('a'));

    } else if (typeName.equals("decimal") || 
               typeName.equals("java.math.BigDecimal")) {
        return new SwitchInputType<BigDecimal>(new BigDecimal("34.58"));

    } else if (typeName.equals("boolean")) {

    }

Answer 1

你可以使用 Map<String, SwitchTypeFactory> :

public interface SwitchTypeFactory {
   SwitchType<?> create(String memberName);
}

...

private static Map<String, SwitchTypeFactory> factories = new HashMap<String, SwitchTypeFactory>();

static {
   factories.put("java.lang.String", new SwitchTypeFactory() {
        @Override
        public SwitchType<?> create(String memberName) {
            return new SwitchInputType<String>(memberName + " ");
        }
    });

    factories.put("char", new SwitchTypeFactory() {
        @Override
        public SwitchType<?> create(String memberName) {
            return new SwitchInputType<Character>(Character.valueOf('a'))
        }
    });
    ...
}

public static SwitchType<?> switchT(final String typeName, final String memberName) {
    return factories.get(typeName).create(memberName);
}