ios - Obj-c - 如果没有搜索结果，则在表格 View 中返回 1 个单元格？

Question

当我的用户在表格 View 内搜索某些内容时，如果没有返回结果，我的应用程序会在表格 View 内显示标准的“无结果”占位符。也就是说，当不存在结果时，我想返回一个填充的单元格(填充有默认数据的单元格)。我怎样才能做到这一点？我尝试了以下操作，但仍然返回“无结果”？

ViewController.m

- (NSInteger) tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section {

     if (tableView == self.searchDisplayController.searchResultsTableView) {

         if ([searchResults count] == 0) {
             return 1; 
         } else {
            return [searchResults count];
         }
   }

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath {

     static NSString *NetworkTableIdentifier = @"sidebarCell";
     self.sidetableView.separatorStyle = UITableViewCellSeparatorStyleNone;

     sidebarCell *cell = (sidebarCell *)[tableView dequeueReusableCellWithIdentifier:NetworkTableIdentifier];
     if (cell == nil) {
        NSArray *nib = [[NSBundle mainBundle] loadNibNamed:@"sidebarCell" owner:self options:nil];
        cell = nib[0];
     }

    if (tableView == self.searchDisplayController.searchResultsTableView) {
        NSDictionary *userName = searchResults[indexPath.row];
        NSString *first = userName[@"first name"];
        NSString *last = userName[@"last name"];

        [[cell username] setText:[NSString stringWithFormat:@"%@ %@", first, last]];

        NSDictionary *userlast = searchResults[indexPath.row];
        [[cell lastName] setText:userlast[@"last name"]];

        NSDictionary *userBio = searchResults[indexPath.row];
        [[cell userDescription] setText:userBio[@"userbio"]];

        NSString *area = userName[@"neighbourhood"];
        NSString *city = userName[@"city"];

        [[cell areaLabel] setText:[NSString stringWithFormat:@"%@, %@", area, city]];

        NSString *profilePath = searchResults[indexPath.row][@"photo_path"];

        [cell.usermini sd_setImageWithURL:[NSURL URLWithString:profilePath]];

        if ([searchResults count] == 0) {
            NSLog(@"SEARCH RESULTS ARE %@", searchResults);

            [[cell username] setText:[NSString stringWithFormat:@"%@", self.searchBar.text]];
            [[cell lastName] setText:userlast[@""]];
            [[cell userDescription] setText:@"This friend is not on the app (yet!) Tap to invite them."];
            [[cell areaLabel] setText:[NSString stringWithFormat:@""]];

            NSString *profileDefault = @"http://url.com/user.png";

            [cell.usermini sd_setImageWithURL:[NSURL URLWithString:profileDefault]];

            return cell;
        }
        return cell;
    }

Answer 1

我真的不建议这样做，因为如果没有搜索结果，您应该返回一个空列表。这符合用户界面指南。但是，如果您坚持，您可以创建一个默认对象并使用该对象初始化 searchResults 数组，并从 numberOfRows 方法返回 1。像这样:

- (NSInteger) tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section
{

  if (tableView == self.searchDisplayController.searchResultsTableView) {

    if ([searchResults count] == 0) {

      NSDictionary *dict = [NSDictionary dictionaryWithObjects:@[@“Enter First Name”, @“Enter Last Name”, @“Enter User Bio”, @“Enter Neighborhood”, @“Enter City”, @“Enter Photo Path”]
      forKeys: @[@“first_name”, @“last_name, @“userbio”, @“neighbourhood”, @“city”, @“photo_path”];

      searchResults = [NSArray arrayWithObjects: dict, nil];

      return 1; 

    } 

    else {
            return [searchResults count];

    }

 }

而且，您可以大大简化 cellForRowAtIndexPath 代码，如下所示:

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{



   static NSString *NetworkTableIdentifier = @"sidebarCell";

    self.sidetableView.separatorStyle = UITableViewCellSeparatorStyleNone;

    sidebarCell *cell = (sidebarCell *)[tableView dequeueReusableCellWithIdentifier:NetworkTableIdentifier];
    if (cell == nil)

    {

        NSArray *nib = [[NSBundle mainBundle] loadNibNamed:@"sidebarCell" owner:self options:nil];
        cell = [nib objectAtIndex:0];
    }



    if (tableView == self.searchDisplayController.searchResultsTableView) {

        //Note, I like to name my local variables the same as the dictionary keys just to eliminate any confusion
        NSDictionary *userObject = [searchResults objectAtIndex:indexPath.row];
        NSString *first_name = [userObject objectForKey:@"first name"];
        NSString *last_name = [userObject objectForKey:@"last name"];
        NSString *userbio = [userObject objectForKey:@“userbio”];
        NSString *neighbourhood = [userObject objectForKey:@“neighbourhood”];
        NSString *city = [userObject objectForKey:@“city”];
        NSString *photo_path = [userObject objectForKey:@“photo_path”];

        [[cell username] setText:[NSString stringWithFormat:@"%@ %@", first_name, last_name]];

        [[cell lastName] setText:last_name];

        [[cell userDescription] setText:userbio];

        [[cell areaLabel] setText:[NSString stringWithFormat:@"%@, %@", neighbourhood, city]];

        [[cell usermini] sd_setImageWithURL:[NSURL URLWithString:photo_path]];

    }

    return cell;

}