ios - Swift:在与 View 匹配的tapGestureRecognizer中播放声音

Question

在 forEach 方法中，我得到了一组 View (一个 View 是一张带有动物图像的卡片)。这是一个卡片组 View ，当向左或向右滑动时，会显示下一张卡片。所以我想在 UITapgestureRecognize 中播放与 View 匹配的声音。

动物库存:

class AnimalsStock {

    var list = [Animal]()
    init() {

        let item =  Animal(name: "Bear", soundUrl: "Bear", imageName: "Bear")

        list.append(item)

        list.append(Animal(name: "Cat", soundUrl: "Cat", imageName: "Cat"))
        list.append(Animal(name: "Chicken", soundUrl: "Chicken", imageName: "Chicken"))
        list.append(Animal(name: "Cow", soundUrl: "Cow", imageName: "Cow"))
}
}

主视图 Controller

HomeController: UIViewController {
   func setupCards() {

        allAnimals.list.forEach { (animal) in   
            let cardView = CardView(frame: .zero)
            cardView.imageView.image = UIImage(named: animal.imageName)
            cardView.animalLabel.text = animal.name
            cardDeckView.addSubview(cardView)
            cardView.fillSuperview()
        }

    }
}

并使用 UITapgestureRecognizer 文件

 class CardView: UIView {

@objc fileprivate func tapCard(recognizer: UITapGestureRecognizer) {
        // Here, I would like to implement a method that plays a sound that matches to the image
        pulseCard()

    }
}

播放声音方法:

var player : AVAudioPlayer?

func playSound(soundUrl: String) {
    guard let url = Bundle.main.url(forResource: soundUrl, withExtension: "mp3") else { return }
    do
    {
        try AVAudioSession.sharedInstance().setCategory(AVAudioSession.Category.playback)
        try AVAudioSession.sharedInstance().setActive(true)

        player = try AVAudioPlayer(contentsOf: url)
        guard let player = player else { return }

        player.play()
    } catch let error {
        print(error.localizedDescription)
    }
}
func stopSound() {
    if player != nil {
        player?.stop()
    }

}

提前致谢

Answer 1

您可以在 for-each 循环中为每个 CardView 分配一个唯一的标记，方法是使其枚举项目，然后使用该标记/索引访问您的动物列表以获取网址。

或者，您始终可以使 CardView 具有 Animal 属性并分配该属性，因此 CardView 只需读出动物即可已分配。