java - map 旋转90度？

Question

我有一个 Grid 类，它管理所有 map 功能。问题是，pacman map 逆时针旋转了 90 度。

外观

它应该是什么样子

我通过将 grid[x][y] 替换为 isWall() 内的 grid[y][x] 获得了“固定”版本(一种不整洁、不正确的方法)

这是 Grid 类的完整代码；

package com.jackwilsdon.pacman.game;

import org.newdawn.slick.Graphics;

public class Grid {
    public static final int BLOCK_SIZE = 20;

    public int[][] grid = null;

    public Grid()
    {
        grid = new int[][]  {   {0,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,0},
                                {0,1,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,1,0},
                                {0,1,0,1,1,0,1,1,1,0,1,0,1,1,1,0,1,1,0,1,0},
                                {0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0},
                                {0,1,0,1,1,0,1,0,1,1,1,1,1,0,1,0,1,1,0,1,0},
                                {0,1,0,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,0,1,0},
                                {0,1,1,1,1,0,1,1,1,0,1,0,1,1,1,0,1,1,1,1,0},
                                {0,0,0,0,1,0,1,0,0,0,0,0,0,0,1,0,1,0,0,0,0},
                                {0,0,0,0,1,0,1,0,1,1,0,1,1,0,1,0,1,0,0,0,0},
                                {0,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,0},
                                {0,0,0,0,1,0,1,0,1,1,1,1,1,0,1,0,1,0,0,0,0},
                                {0,0,0,0,1,0,1,0,0,0,0,0,0,0,1,0,1,0,0,0,0},
                                {0,1,1,1,1,0,1,0,1,1,1,1,1,0,1,0,1,1,1,1,0},
                                {0,1,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,1,0},
                                {0,1,0,1,1,0,1,1,1,0,1,0,1,1,1,0,1,1,0,1,0},
                                {0,1,0,0,1,0,0,0,0,0,0,0,0,0,0,0,1,0,0,1,0},
                                {0,1,1,0,1,0,1,0,1,1,1,1,1,0,1,0,1,0,1,1,0},
                                {0,1,0,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,0,1,0},
                                {0,1,0,1,1,1,1,1,1,0,1,0,1,1,1,1,1,1,0,1,0},
                                {0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0},
                                {0,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,0}     };
    }

    public boolean isWall(int x, int y)
    {
        if (x >= 0 && x < grid.length && y >= 0 && y < grid[0].length)
        {
            return grid[y][x] == 1;
        }

        return true;
    }

    public void draw(Graphics g)
    {
        for (int cX = 0; cX < grid.length; cX++)
        {
            for (int cY = 0; cY < grid[cX].length; cY++)
            {
                if (this.isWall(cX, cY))
                {
                    g.fillRect(cX*Grid.BLOCK_SIZE, cY*Grid.BLOCK_SIZE, Grid.BLOCK_SIZE, Grid.BLOCK_SIZE);
                }
            }
        }
    }
}

我的代码是否犯了愚蠢的错误？

我不想调换 x 和 y，因为这不再是二维数组的正确格式。

Answer 1

我在您的代码中看到的问题是边界检查不正确。也就是说，这段代码:

if (x >= 0 && x < grid.length && y >= 0 && y < grid[0].length)
{
    return grid[y][x] == 1;
}

实际上应该是

if (x >= 0 && x < grid[0].length && y >= 0 && y < grid.length)
{
    return grid[y][x] == 1;
}

您当前的代码之所以有效，是因为尺寸相等( map 是方形的)。

您在 draw 函数中有同样的错误。也就是说，应该是

for (int cY = 0; cY < grid.length; cY++)
{
    for (int cX = 0; cX < grid[cY].length; cX++)
    {
        if (this.isWall(cX, cY))
        {
            g.fillRect(cX*Grid.BLOCK_SIZE, cY*Grid.BLOCK_SIZE, Grid.BLOCK_SIZE, Grid.BLOCK_SIZE);
        }
    }
}

在任何情况下，grid[y][x] 都是正确的而不是 grid[x][y] 因为 grid[i] 指的是二维数组的索引 i 处的行，而不是列。