php - 具有多个 Mysql 结果的交替 CSS 样式

Question

我有一个网站，有人在他们的位置搜索 x 产品，该网站会返回结果列表。

if(isset($_POST['zip'])){
$qry="SELECT business_id FROM ".TBL_BUSINESS." WHERE zip LIKE '%".$_POST['zip']."%'";
$rs = mysql_query($qry);

$rec = array();

while(($row = mysql_fetch_array($rs)) !== FALSE ){
    $rec[] = $row[0];
}

if(!empty($rec[0])){

    echo "Products for this location<br/>";

    foreach ($rec as $result)
    {
        $bid = $result;
        $qry2 = "SELECT * FROM products WHERE business_id = '".$bid."'";
        $rs2 = mysql_query($qry2);
        $rec2 = mysql_fetch_array($rs2);
        ?>
            <div class="norm">
                <img src="admin/product/img/<?php echo $rec2['image']; ?>" height="40" width="40" />
                <h3><a href="product.php?id=<?php echo $rec2['id']; ?>"><?echo $rec2['name'];?>&nbsp;&nbsp;<?php echo $rec2['prodvalue']?></a></h3>
                <div class="prodlistMeta">
                    <a class='view' href="product.php?id=<?php echo $rec2['id']; ?>">View Product</a>
                    <a class="print" href="#">Print</a>
                </div>
            </div>
        <?php
    }
}
else
{
    echo "No Product is added for this location";
}

}?>

交替 <div class="norm"> 的最佳方式是什么？与 <div class="alt"> ？

Answer 1

保留一个计数器并使用它的值模 2 来确定类应该是“norm”还是“alt”。

 $rec2 = mysql_fetch_array($rs2);
 $count++;
   ?>
      <div class="<?php echo($count%2?"norm":"alt"); ?>">