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java - SQlite WHERE 语句不起作用?

转载 作者:行者123 更新时间:2023-11-29 05:45:51 28 4
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我正在制作一个应用程序,用于存储书名、添加日期和需要归还图书的日期。下面,我展示了 where 语句,该语句获取所有在今天和两天之间归还的书籍,并以 ListView 的形式返回。但是,它不起作用,我不确定哪里出错了:

    public Cursor fetchAllDue() {

//get todays date
Calendar cal=Calendar.getInstance();
int currentDay=cal.get(Calendar.DAY_OF_MONTH);

//Add days on to todays date
cal.set(Calendar.DAY_OF_MONTH, currentDay+2);
cal.getTime(); //Result

//format back to string
String formattedDate = new SimpleDateFormat("dd-MM-yyyy HH:mm").format(cal.getTime());


//get todays date
Calendar cal1=Calendar.getInstance();
int currentDay1=cal1.get(Calendar.DAY_OF_MONTH);

//Atodays date
cal1.set(Calendar.DAY_OF_MONTH, currentDay1);
cal1.getTime(); //Result

//format back to string
String formattedDate1 = new SimpleDateFormat("dd-MM-yyyy HH:mm").format(cal1.getTime());


//body = date added, needs to be changed
return mDb.query(DATABASE_TABLE, new String[] { KEY_ROWID, KEY_TITLE,
KEY_BODY, KEY_EXTRA, KEY_DUE }, KEY_DUE + " BETWEEN 'formattedDate1' and 'formattedDate2'", null, null, null, null);
}

这是为“截止日期”输入日期的代码:

                //convert string to int.
int myNum = Integer.parseInt(editbox3.getText().toString());

//get todays date
Calendar cal=Calendar.getInstance();
int currentDay=cal.get(Calendar.DAY_OF_MONTH);

//Add days on to todays date
cal.set(Calendar.DAY_OF_MONTH, currentDay+myNum);
cal.getTime(); //Result

//formate back to string
String formattedDate = new SimpleDateFormat("dd-MM-yyyy HH:mm").format(cal.getTime());


bundle.putString(NotesDbAdapter.KEY_DUE,formattedDate
.toString());

日期都是字符串。谁能帮忙?

最佳答案

您的查询有误。您使用 formattedDate1formattedDate2 但您的代码正在设置 formattedDateformattedDate1,更不用说这些非常重要的事实不会进入您的查询,因为您没有通过它。它应该是这样的:

String where = KEY_DUE + " BETWEEN ? AND ?";
String[] args = { String.valueOf(formattedDate1), String.valueOf(formattedDate2) };
return mDb.query(DATABASE_TABLE, where, args, null, null, null, null);

关于java - SQlite WHERE 语句不起作用?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/15889076/

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