ios - 搜索过滤器必须从 [[String : Any]]() array to new filtered array?

Question

我有一个 tableview ，我正在其中加载我命名为 PlaylistArray 的数组中的所有详细信息。我有一个搜索页面，用户可以从 [[String: Any]] 类型的 playlistArray 中搜索。我不知道如何将 PlayListArray 中用户给出的搜索文本过滤为 filteredArray。我已附上 PlaylistArray 响应供您引用。

这是我之前尝试过的用于过滤PlaylistArray的代码。

 let searchPredicate = NSPredicate(format: "SELF CONTAINS[c] %@", searchController.searchBar.text!)
 let array = (constantsList.playTypeArray.lectureArraymp3 as NSArray).filtered(using: searchPredicate)
          //  filtered_Array.add(array)
 print(array)

我需要搜索用户提供的搜索文本，并且我们必须将搜索文本与 playlistArray 的 title 标签进行比较。当两者相同时，我需要向过滤数组显示特定数组索引的完整详细信息。

播放列表数组:

[["title": Kaṭha-Bhāṣyam-41 Mantra 1-2-20, "image_url": https://www.imaginetventures.name/swamijione/wp-content/uploads/2019/01/gitanew.png, "mp3": https://www.imaginetventures.name/swamiji/wp-content/uploads/2018/12/01-PURU],["title": Kaṭha-Bhāṣyam-41 Mantra 1-2-20, "image_url": https://www.imaginetventures.name/swamijione/wp-content/uploads/2019/01/gitanew.png, "mp3": https://www.imaginetventures.name/swamiji/wp-content/uploads/2018/12/01-PURU],["title": Kaṭha-Bhāṣyam-41 Mantra 1-2-20, "image_url": https://www.imaginetventures.name/swamijione/wp-content/uploads/2019/01/gitanew.png, "mp3": https://www.imaginetventures.name/swamiji/wp-content/uploads/2018/12/01-PURU]]

Answer 1

这是一个使用 filter API 的 swift 解决方案。在这里阅读更多相关信息:https://developer.apple.com/documentation/swift/sequence/3018365-filter

let array = [["title": "Kaṭha-Bhāṣyam-41 Mantra 1-2-20", "image_url": "https://www.imaginetventures.name/swamijione/wp-content/uploads/2019/01/gitanew.png"],
             ["title": "Kaṭa-Bhāṣyam-41 Mantra 1-2-20", "image_url": "https://www.imaginetventures.name/swamijione/wp-content/uploads/2019/01/gitanew.png"]]

guard let searchText = searchController.searchBar.text else {return} //Or use if-let
let filteredArray = array.filter { (object) -> Bool in
    guard let title = object["title"] as? String else {return false}
    return title?.contains(searchText) ?? false
}