java - 在java中对二维数组进行排序(对所有字母进行排序)

Question

我想对以下二维数组进行排序:

String[][] rows = {
            {"M","O","N","K","E","Y"},
            {"D","O","N","K","E","Y"},
            {"M","A","K","E"},
            {"M","U","C","K","Y"},
            {"C","O","O","K","Y"},
            };

我希望得到以下结果:

A C C D E E E K K K K K M M M N N O O O O U Y Y Y Y

但是我不知道该怎么做!!我找不到任何关于 2D 数组排序的好例子。

如您所见，我不想按列或行排序，但我只想对数组中的所有字符进行排序。通过这种方式，我可以计算每个字符在二维数组中的位置。

如果您知道如何计算二维数组中每个字符的数量，那对我来说也是一个很好的解决方案。

Answer 1

这将使用 Collections.sort 将二维数组排序为 List 对象。

import java.util.List;
import java.util.ArrayList;
import java.util.Collections;

public class Test {
    public static void main(String[] args) {
        String[][] rows = {
                {"M","O","N","K","E","Y"},
                {"D","O","N","K","E","Y"},
                {"M","A","K","E"},
                {"M","U","C","K","Y"},
                {"C","O","O","K","Y"},
            };

        List<String> list = new ArrayList<String>();

        // Add all strings to list.
        for (String[] row : rows) {
            for (String s : row) {
                    list.add(s);
            }
        }

        Collections.sort(list); // Sort the list.
    }
}

您可以使用以下方法将列表转换为基本数组:

String[] arr = list.toArray(new String[list.size()]);

要计算数组中的每个字符，请查看 jlordo's回答。