gpt4 book ai didi

mysql - 如何进行 SQL 查询以从两个单独的表中获取两次连接的用户数据?

转载 作者:行者123 更新时间:2023-11-29 05:38:14 25 4
gpt4 key购买 nike

我有一个评论列表。对于每条评论,都可能有子评论(有点像 Stack Overflow 中对答案的评论)。

我不确定该怎么做,是在一个查询中查询所有这些。到目前为止我有这个:

select 
problem_id , suggester_id , solution , suggested_solution_id ,
DAYOFMONTH(solution_date) , DAYNAME(solution_date) , YEAR(solution_date) ,
MONTH(solution_date) , first_name , last_name , email ,
small_thumb , mid_thumb , solution_name , suggested_solution_comment.comment
from suggested_solutions
left join users
on suggested_solutions.suggester_id = users.user_id
left join member_photo
on suggested_solutions.suggester_id = member_photo.member_id
left join suggested_solution_discussion
on suggested_solutions.suggested_solution_id = suggested_solution_discussion.suggested_solution_id
left join users
on suggested_solution_discussion.commenter_id = users.user_id
left join member_photo
on suggested_solution_discussion.suggester_id = member_photo.member_id
where problem_id = id;

suggested_solution_discussion是评论的子评论。所以我最终将 suggested_solution 表与 users 表连接起来,为了显示谁发表了子评论,我最终不得不将 suggested_solution_discussion 表与 users 表连接起来。

我得到这个错误:

ERROR 1066 (42000): Not unique table/alias: 'users'

进行此查询的正确方法是什么?

最佳答案

你已经加入了两次users表,需要给每一次都提供一个别名,以便于区分

...
left join users as users_1 on suggested_solutions.suggester_id = users_1.user_id
...
left join users as users_2 on suggested_solution_discussion.commenter_id = users_2.user_id
...

关于mysql - 如何进行 SQL 查询以从两个单独的表中获取两次连接的用户数据?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/8914269/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com