java - 具有 2 种颜色的 ListView 不交错

Question

我正在尝试使用 2 种颜色创建一个 ListView，交错颜色为白色和灰色。在我的 getView 方法适配器中，我执行以下代码:

if(position % 2 == 0){
    v.setBackgroundColor(Color.WHITE);
}else{
    v.setBackgroundResource(R.color.light_grey_listas);
}
 return v;

但在我的屏幕上，有时一组线条颜色相同。例如，3 行具有灰色背景颜色，或者当我在 ListView 中导航时，行更改为错误的颜色

Answer 1

以下是展示的步骤。

Step1.1) 对奇数和偶数位置列表项使用两个选择器

artists_list_backgroundcolor.xml

<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
 <item
 android:state_selected="false"
    android:state_pressed="false"
    android:drawable="@color/grey" />
<item android:state_pressed="true"
    android:drawable="@color/itemselected" />
<item android:state_selected="true"
 android:state_pressed="false"
    android:drawable="@color/itemselected" />
</selector>

步骤 1.2)artists_list_background_alternate.xml

<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
 <item
 android:state_selected="false"
    android:state_pressed="false"
    android:drawable="@color/sign_out_color" />
<item android:state_pressed="true"
    android:drawable="@color/login_hover" />
<item android:state_selected="true"
 android:state_pressed="false"
    android:drawable="@color/login_hover" />
</selector>

第二步)颜色.xml

<?xml version="1.0" encoding="utf-8"?>
<resources>

    <color name="survey_toplist_item">#EFEDEC</color>
    <color name="survey_alternate_color">#EBE7E6</color>
    <color name="grey">#ffffff</color>
    <color name="itemselected">#EDEDED</color>
    <color name="login_hover">#E5F5FA</color>
    <color name="sign_out_color">#e84040</color>

</resources>



@Override
    public View getView(int position, View convertView, ViewGroup parent) {
        View view = convertView;
        if (view == null) {
            view = lInflater.inflate(R.layout.listitem, parent, false);
        }

        if (position % 2 == 0) {
            view.setBackgroundResource(R.drawable.artists_list_backgroundcolor);
        } else {
            view.setBackgroundResource(R.drawable.artists_list_background_alternate);
        }

        ((TextView) view.findViewById(R.id.heading)).setText(data.get(position));

        return view;
    }
}

您可以在下面的链接中获得完整的描述

http://amitandroid.blogspot.in/2013/03/android-listview-with-alternate-list.html