mysql - UPDATE table1 SET column1 = (SUM(table2{& table3} WHERE table2_id1 = id1) WHERE id1 = table2_id1

Question

我想根据主要应用于表 2 的总和更新表 1，但包括表 3 中的单个值。

table2 有一个列是 FKd 到 table1 的 id 列，并且总和基于它们匹配。

UPDATE table1, table2 
SET table1.column1 = 
(SELECT SUM( (SELECT constant FROM table3) +
          (SELECT table2.sum_number 
           WHERE table2.table2_id1 = table1.id) ) ) 
WHERE table1.id = table2.table2_id1;

这对我不起作用。

非常感谢!

编辑:给定错误

#1064 - You have an error in your SQL syntax; check the manual that corresponds 
 to your MySQL server version for the right syntax to use near 
 'WHERE table2.table2_id1 = table1.id) ) ) WHERE table1.id = table2.table2_id1;'

Answer 1

UPDATE table1, table2 
SET table1.column1 = 
(
    SELECT SUM( 
        (SELECT constant FROM table3) +
        (SELECT table2.sum_number *** WHERE table2.table2_id1 = table1.id) 
    ) 
) 
WHERE table1.id = table2.table2_id1;

上面带星号的区域没有“FROM table2,table1”。