java - 删除文本中的一行，如果

Question

你好，我的问题是我有一个类似这样的文本:

something1
[ something2
something3
[ something4

我想在 java 中编写一个代码来读取该文本并搜索一个字符，在本例中为“[”，当它找到它时，删除整行，在本例中为“[ something2"，然后继续搜索那个角色所以最后我会得到这样的东西

something1
something3

我已经在搜索类似的东西并且找到了这种方法

File inputFile = new File("myFile.txt");
File tempFile = new File("myTempFile.txt");

BufferedReader reader = new BufferedReader(new FileReader(inputFile));
BufferedWriter writer = new BufferedWriter(new FileWriter(tempFile));

String lineToRemove = "bbb";
String currentLine;

while((currentLine = reader.readLine()) != null) {
    // trim newline when comparing with lineToRemove
    String trimmedLine = currentLine.trim();
    if(trimmedLine.equals(lineToRemove)) continue;
    writer.write(currentLine);
}

boolean successful = tempFile.renameTo(inputFile);

该代码删除了其中包含“bbb”的整行，这里的问题是只删除了其中只有且难以捉摸的 bbb 的行举例说明

something1
bbb
something3
bbb something

运行代码后

something1
something3
bbb something

所以我尝试修改代码以搜索字符 [ 然后删除整行。但我做不到，所以我希望有人能帮助我。

Answer 1

试试这个:

File inputFile = new File("myFile.txt");
File tempFile = new File("myTempFile.txt");

BufferedReader reader = new BufferedReader(new FileReader(inputFile));
BufferedWriter writer = new BufferedWriter(new FileWriter(tempFile));

String lineToRemove = "bbb";
String currentLine;

while((currentLine = reader.readLine()) != null) {
    // trim newline when comparing with lineToRemove
    String trimmedLine = currentLine.trim();
    if(!trimmedLine.contains(lineToRemove))
    { 
      writer.write(currentLine);
    }
}

boolean successful = tempFile.renameTo(inputFile);