ios - 我想从数组中的数组中搜索？参见示例

Question

我必须从数组内的数组中进行搜索。但我做不到。请参阅数组示例:

[
    {
        "hospital_name": "Medical Hospital", 
        "address": "1/127 India ", 
        "facilities_data": [
            {
                "name": "Speciality", 
                "facilities_list": [
                    {
                        "facilities_name": "Andrology"
                    }, 
                    {
                        "facilities_name": "Cosmetology"
                    }
                ]
            },
            {
                "name": "Facilities", 
                "facilities_list": [
                    {
                        "facilities_name": "ICU"
                    }, 
                    {
                        "facilities_name": "Multispeciality"
                    }, 
                    {
                        "facilities_name": "OPD"
                    }, 
                    {
                        "facilities_name": "Physical Therapy"
                    }
                ]
            }
        ]
    }
]

我必须使用医院名称、地址和设施名称进行搜索

我现在正在这样做，我正在获得医院名称和地址的成功结果。 但不适用于设施名称。

func getAllSearchedArrayList(txt: String) {
      let namePredicate1 = NSPredicate(format: "hospital_name contains[c] %@ || facilities_name contains[c] %@ || address contains[c] %@", txt, txt, txt);        
      var searchedArray1: Array<Any>!
      searchedArray1 = self.hospitalArray.filter { namePredicate1.evaluate(with: $0) };
      self.searchedHospitalArray = searchedArray1
      if self.searchedHospitalArray.count == 0 {
          self.hospitalTableView.reloadData()
      }
      else {
          self.hospitalTableView.reloadData()
      }
  } 

请帮帮我。

Answer 1

将数组构造为如下结构:

    struct Hospital{
        let hospital_name : String!
        let address : String!
        let facilities_Data : [Facilities_Data]!
    }

    struct Facilities_Data{
        let name : String!
        let facilities_list : [String]!
    }

    var hospitals = [Hospital]()    // parse your array to struct first
    var filteredHospitals = hospitals     // use filteredHospitals to fill your tableview data instead of the original hospitals array to keep the original data intact.

    func getAllSearchedArrayList(searchText: String){

        //reuse original data if no searchText else starts to filter

        filteredHospitals = searchText.isEmpty ? hospitals : hospitals.filter({ (hospital) -> Bool in
            return hospital.hospital_name.range(of: searchText, options: .caseInsensitive, range: nil, locale: nil) != nil || hospital.address.range(of: searchText, options: .caseInsensitive, range: nil, locale: nil) != nil || hospital.facilities_Data.contains(where: { (data) -> Bool in
                return data.facilities_list.contains(where: { (name) -> Bool in
                    return name.range(of: searchText, options: .caseInsensitive, range: nil, locale: nil) != nil
                })
            })
        })
        self.tableView.reloadData()
    }

这里的主要思想是解决可怕的字典数组问题，并将它们分成更小的代码块和可识别的类型，以便您可以使用该特定类型进行搜索。 (在本例中使用 range(of:) 的字符串。

我个人将其与搜索栏委托(delegate)结合使用: search(_ searchBar: UISearchBar, textDidChange searchText: String) 因为它允许用户每次在搜索栏中输入内容时都可以看到结果，而不是仅仅输入整个字符串看到没有结果，这样tableview就会不断刷新并显示越来越少的结果。