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iOS 12.4.1 发布导致 iPad 设备被苹果商店拒绝崩溃

转载 作者:行者123 更新时间:2023-11-29 05:26:44 38 4
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你好,我是 IOS swift 的新手,

我的应用程序在 iPhone/iPad 模拟器上运行良好,但是,我收到了来自苹果应用商店的应用程序拒绝消息。

我认为崩溃原因是调用 api,因为根据拒绝消息,他们尝试使用电子邮件和密码登录,一旦他们点击提交按钮,应用程序就会崩溃,应用程序在提交按钮点击时我们调用了登录API。

苹果的崩溃报告

{"app_name":"gogetGONE","timestamp":"2019-09-24 13:37:46.50 -07
00","app_version":"6.0","slice_uuid":"5958bf7b-689e-306b-8b81-0ad61cdb32b2","adam_id":1466582359,"build_version":"1","bundleID":"com.gogetgone.gogetgonepro","share_with_app_devs":false,"is_first_party":false,"bug_type":"109","os_version":"iPhone OS 12.4.1 (16G102)","incident_id":"D1DE09EF-3CC3-47C8-A03B-49108C8B3BFC","name":"gogetGONE"}
Incident Identifier: D1DE09EF-3CC3-47C8-A03B-49108C8B3BFC
CrashReporter Key: c201dc074338fd6214efc8c4bfbbe19377d79d89
Hardware Model: xxx
Process: gogetGONE [4259]
Path: /private/var/containers/Bundle/Application/E7D0CB5E-929F-43F5-AEA9-400B122CD35E/gogetGONE.app/gogetGONE
Identifier: com.gogetgone.gogetgonepro
Version: 1 (6.0)
AppStoreTools: 11A1002b
Code Type: ARM-64 (Native)
Role: Non UI
Parent Process: launchd [1]
Coalition: com.gogetgone.gogetgonepro [1698]


Date/Time: 2019-09-24 13:37:46.3466 -0700
Launch Time: 2019-09-24 13:20:36.4938 -0700
OS Version: iPhone OS 12.4.1 (16G102)
Report Version: 104

Exception Type: EXC_BREAKPOINT (SIGTRAP)
Exception Codes: 0x0000000000000001, 0x0000000102e50348
Termination Signal: Trace/BPT trap: 5
Termination Reason: Namespace SIGNAL, Code 0x5
Terminating Process: exc handler [4259]
Triggered by Thread: 0

Thread 0 name: Dispatch queue: com.apple.main-thread
Thread 0 Crashed:
0 gogetGONE 0x0000000102e50348 0x102df8000 + 361288
1 gogetGONE 0x0000000102e1c1f0 0x102df8000 + 147952
2 Alamofire 0x0000000102f4a920 0x102f1c000 + 190752
3 Alamofire 0x0000000102f2d074 0x102f1c000 + 69748
4 libdispatch.dylib 0x0000000182983a38 0x182924000 + 391736
5 libdispatch.dylib 0x00000001829847d4 0x182924000 + 395220
6 libdispatch.dylib 0x0000000182932008 0x182924000 + 57352
7 CoreFoundation 0x0000000182ed732c 0x182e2d000 + 697132
8 CoreFoundation 0x0000000182ed2264 0x182e2d000 + 676452
9 CoreFoundation 0x0000000182ed17c0 0x182e2d000 + 673728
10 GraphicsServices 0x00000001850d279c 0x1850c8000 + 42908
11 UIKitCore 0x00000001af5c4c38 0x1aed08000 + 9161784
12 gogetGONE 0x0000000102dff9f4 0x102df8000 + 31220
13 libdyld.dylib 0x00000001829958e0 0x182994000 + 6368

代码片段信息.Plist。

<key>NSAppTransportSecurity</key>
<dict>
<key>NSAllowsArbitraryLoads</key>
<true/>
<key>NSExceptionDomains</key>
<dict>
<key>localhost</key>
<dict>
<key>NSExceptionAllowsInsecureHTTPLoads</key>
<true/>
</dict>
</dict>
</dict>

登录.swift

func save() {
let parameters: Parameters = [
"email": self.emailTextField.text!,
"password": self.passwordTextField.text!,
]
loginButton.isEnabled = false
Alamofire.request(ApiRequest.API_URL+"/auth/login", method : .post,parameters:parameters).responseJSON { response in
if((response.result.value) != nil) {
let json = JSON( response.result.value!)
print("JSON: \(json)") // serialized json response
if(json["success"].boolValue){
//TODO login login
self.gotoHome()
}
else{
self.showAlert(for: json["message"].stringValue)
}
}
}

}

最佳答案

您的信息 plist 应该包含实时服务器的 DNS,而不是 localHost

<key>NSAppTransportSecurity</key>
<dict>
<key>NSAllowsArbitraryLoads</key>
<true/>
<key>NSExceptionDomains</key>
<dict>
<key>localhost</key>
<dict>
<key>NSExceptionAllowsInsecureHTTPLoads</key>
<true/>
</dict>
</dict>
</dict>

据我所知,它可能是零响应或类型转换导致了问题。

  • 首先替换

        if((response.result.value) != nil)

    if let swiftyResponse=response, swiftyResponse.result.value !=nil { 
    guard let json = swiftyResponse.result.value else{return }}
  • 进一步验证json["success"].boolValue是否确实返回bool值或者success包含字符串或Integer等。

  • 更多检查您的 self.gotoHome 方法,我建议您将其也发布到您的代码中

关于iOS 12.4.1 发布导致 iPad 设备被苹果商店拒绝崩溃,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58097448/

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