java.lang.IndexOutOfBoundsException : Index: 3, 大小:3

Question

我不断得到

Exception in thread "main" java.lang.IndexOutOfBoundsException: Index: 3, Size: 3
at java.util.ArrayList.rangeCheck(Unknown Source)
at java.util.ArrayList.get(Unknown Source)
at hartman.ShortestString.printShortestString(ShortestString.java:40)
at hartman.ShortestString.main(ShortestString.java:28)

我该如何解决这个问题？

package hartman;

import java.util.ArrayList;
import java.util.Scanner;

public class ShortestString {

    public static void main(String[] args) {
        System.out.printf("WELCOME TO SHORTEST STRING\n\n");
        System.out.printf("Type \".\" when done entering data.\n\n");

        ArrayList<String> myArray = new ArrayList<>();
        Scanner keyboard = new Scanner(System.in);
        boolean keepAsking = true;

        while (keepAsking) {
            System.out.printf("Enter string: ");
            String userInput = keyboard.nextLine();

            if (userInput.equals(".")) {
                keepAsking = false;
            } else {
                myArray.add(userInput);
            }
        }

        printShortestString(myArray);
        System.out.printf("\n\nGOODBYE!\n");
        keyboard.close();
    }

    public static void printShortestString(ArrayList<String> myArray) {

        int index;
        int index1 = 1;

        for (index = 0; index < myArray.get(index).length(); index++) {
            if (myArray.get(index).length() < myArray.get(index1).length()) {
                System.out.printf("\nShortest string is \"%s\" with length %d",
                        myArray.get(index), myArray.get(index).length());
            } else {
                index1++;
            }
        }
        return;
    }
}

Answer 1

尝试使用 for (index = 0; index < myArray.length(); index++) {对于第 40 行。您在元素 index 处使用字符串的长度，而不是 ArrayList 的长度。