php - 在 mysql_fetch_array 中调用两个查询？

Question

大家下午好，关于这个获取查询的快速问题。

<?php
    $sql = "SELECT * FROM products ";
        if(isset($_POST['Submit'])){
            if(empty($_POST['Search'])){
                $error = true;
            }else{
            $searchq = mysql_real_escape_string($_POST['Search']);
            $searchq = preg_replace("#[^0-9a-z]#i","",$searchq);
            $sql .= "WHERE type LIKE '%$searchq%' or name LIKE '%$searchq%'";       
        } 
    } $query = mysql_query($sql) or die(mysql_error());

        $sql1 = "SELECT * FROM products ";
        if(isset($_GET['q'])){
            $categories = mysql_real_escape_string($_GET['q']);
            $sql1 .= "WHERE type LIKE '%$categories%'";       
        } $query1 = mysql_query($sql1) or die(mysql_error());  

     ?>





<?php while ($row = mysql_fetch_array($query) and $row = mysql_fetch_array($query1)) { ?>
        <div class="prod_box">
           <div class="top_prod_box"></div>
            <div class="center_prod_box">
              <div class="product_title"><a href="productsview.php<?php echo '?id='.$row['serial']; ?>"><b><?php echo $row['name']?></a></div>
              <div class="product_img"><a href="productsview.php<?php echo '?id='.$row['serial']; ?>"><img src="<?php echo $row['picture']?>" height="100" width="120" /></a></div>
              <div class="prod_price"><span class="reduce"><?php if($row['rprice'] > 0) {echo "£"; echo $row['rprice'];}?></span> <span class="price"><big style="color:green">£<?php echo $row['price']?></big></span></div>
            </div>
            <div class="bottom_prod_box"></div>
            <div align="center" class="prod_details_tab"> <input type="button" value="Add to Cart" onclick="addtocart(<?php echo $row['serial']?>)" /></td> </div>
            </div>
            <?php } ?></p>

有人看到这里有什么不对吗？查询获取很好，但不正确，即使表单甚至没有提交，它也会获取其他查询的部分内容。 :\

Answer 1

您可以运行查询一次。只需在创建查询时组合 GET 和 POST。

$noWhere = true;
$sql = "SELECT * FROM products ";

if(isset($_POST['Submit'])){
    if(empty($_POST['Search'])){
        $error = true;
    }else{
        $searchq = mysql_real_escape_string($_POST['Search']);
        $searchq = preg_replace("#[^0-9a-z]#i","",$searchq);
        $sql .= "WHERE type LIKE '%$searchq%' or name LIKE '%$searchq%'";
        $noWhere = false;   
    }
} 
// check if categories got sent
if(isset($_GET['q'])){
    $categories = mysql_real_escape_string($_GET['q']);
    if($noWhere) $sql .= "WHERE type LIKE '%$categories%'";  
    else $sql .= " OR type LIKE '%$categories%'";       
}
$query = mysql_query($sql) or die(mysql_error()); 

?>

<?php while ($row = mysql_fetch_array($query)) { ?>

虽然我必须添加一个评论。您正在使用正式弃用的 mysql() 函数。我应该检查 PDO从 PHP 使用数据库。