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java - 当我在 DBPedia 上运行查询时 CATCH block 中的条件

转载 作者:行者123 更新时间:2023-11-29 05:16:35 25 4
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我有一个问题:

我编写了一段 Java 代码,用于在 DBPedia 上执行一些查询。通常,DBPedia 不可用,我会收到此错误:

SEVERE [http-apr-8080-exec-12] com.sun.xml.ws.server.sei.EndpointMethodHandler.invoke Error making the query, see cause for details
HttpException: 502
at com.hp.hpl.jena.sparql.engine.http.HttpQuery.execGet(HttpQuery.java:340)
at com.hp.hpl.jena.sparql.engine.http.HttpQuery.exec(HttpQuery.java:276)
at com.hp.hpl.jena.sparql.engine.http.QueryEngineHTTP.execSelect(QueryEngineHTTP.java:345)
at WS.TEST.testmethod(TEST.java:184)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:606)
at com.sun.xml.ws.api.server.InstanceResolver$1.invoke(InstanceResolver.java:246)
at com.sun.xml.ws.server.InvokerTube$2.invoke(InvokerTube.java:146)
at com.sun.xml.ws.server.sei.EndpointMethodHandler.invoke(EndpointMethodHandler.java:257)
at com.sun.xml.ws.server.sei.SEIInvokerTube.processRequest(SEIInvokerTube.java:95)
at com.sun.xml.ws.api.pipe.Fiber.__doRun(Fiber.java:629)
at com.sun.xml.ws.api.pipe.Fiber._doRun(Fiber.java:588)
at com.sun.xml.ws.api.pipe.Fiber.doRun(Fiber.java:573)
at com.sun.xml.ws.api.pipe.Fiber.runSync(Fiber.java:470)
at com.sun.xml.ws.server.WSEndpointImpl$2.process(WSEndpointImpl.java:295)
at com.sun.xml.ws.transport.http.HttpAdapter$HttpToolkit.handle(HttpAdapter.java:515)
at com.sun.xml.ws.transport.http.HttpAdapter.handle(HttpAdapter.java:285)
at com.sun.xml.ws.transport.http.servlet.ServletAdapter.handle(ServletAdapter.java:143)
at com.sun.xml.ws.transport.http.servlet.WSServletDelegate.doGet(WSServletDelegate.java:155)
at com.sun.xml.ws.transport.http.servlet.WSServletDelegate.doPost(WSServletDelegate.java:189)
at com.sun.xml.ws.transport.http.servlet.WSServlet.doPost(WSServlet.java:76)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:644)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:725)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:291)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206)
at org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:239)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:219)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:106)
at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:505)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:142)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:79)
at org.apache.catalina.valves.AbstractAccessLogValve.invoke(AbstractAccessLogValve.java:610)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:88)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:534)
at org.apache.coyote.http11.AbstractHttp11Processor.process(AbstractHttp11Processor.java:1081)
at org.apache.coyote.AbstractProtocol$AbstractConnectionHandler.process(AbstractProtocol.java:658)
at org.apache.coyote.http11.Http11AprProtocol$Http11ConnectionHandler.process(Http11AprProtocol.java:277)
at org.apache.tomcat.util.net.AprEndpoint$SocketProcessor.doRun(AprEndpoint.java:2381)
at org.apache.tomcat.util.net.AprEndpoint$SocketProcessor.run(AprEndpoint.java:2370)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1145)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:615)
at org.apache.tomcat.util.threads.TaskThread$WrappingRunnable.run(TaskThread.java:61)
at java.lang.Thread.run(Thread.java:744)

现在,我想在调用此操作时在我的代码中添加一个 TRY/CATCH block :

QueryExecution qe = query(string);

对于这个错误,我必须在 catch 中插入什么条件?

最佳答案

从您的代码看来它抛出了 HttpException。

这样写:

try
{
QueryExecution qe = query(string);
}
catch (HttpException ex)
{
System.out.println (ex.getMessage()); //Optional
ex.printStackTrace(); //Optional
}

另一个捕获可以是 catch (Exception ex) {..}//它将捕获任何问题。但是,如果您知道确切的异常,请使用确切的。

在最后我写了常见的错误打印,但你可以根据你的问题填写它。

关于java - 当我在 DBPedia 上运行查询时 CATCH block 中的条件,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26335610/

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