ios - 如何将文本从 SafariViewController 快速获取到我们的应用程序？

Question

在我的应用程序中，我们使用 Segpay 进行支付，没有合适的 SDK 可以集成，然后我们从支持的 URL 中创建 URL 并在 SafariViewController 中打开它。

当用户成功完成付款时，我们需要将用户带入主页，如何从 SafariViewController 知道状态为成功。

我在 SafariViewController 上收到了来自后端的响应，如下所示，在 webview 页面上:

Answer 1

您可以使用 WKWebview 代替 safari，如下所示。

创建 WKWebView 的属性

private var webView: WKWebView!

按照 viewDidLoad 方法初始化 webview...

let jScript = "var meta = document.createElement('meta'); meta.setAttribute('name', 'viewport'); meta.setAttribute('content', 'width=device-width'); document.getElementsByTagName('head')[0].appendChild(meta);"
let wkUScript = WKUserScript(source: jScript, injectionTime: .atDocumentStart, forMainFrameOnly: true)
let wkUController = WKUserContentController()
wkUController.addUserScript(wkUScript)

let webConfiguration = WKWebViewConfiguration()
webConfiguration.userContentController = wkUController

webView = WKWebView(frame: view.bounds, configuration: webConfiguration)
webView.navigationDelegate = self
view.addSubview(webView)
let url = URL(string: "https://...") //set url to load in webview
let req = URLRequest(url: url)
webView.load(req)

实现WKWebView的以下委托(delegate)方法。

func webView(_ webView: WKWebView, didFinish navigation: WKNavigation!) {
    webView.evaluateJavaScript("document.getElementById('response_success').textContent", completionHandler: { (html, error) in

        if let content = html as? String {
            print(content)

            if content.lowercased().contains("ok") { //here you can place the status coming from server for comparison

               //handle success response
            }
        }
    })
    webView.evaluateJavaScript("document.getElementById('response_fail').textContent", completionHandler: { (html, error) in

        if let content = html as? String {
            print(content)

            if content.lowercased().contains("fail") { //here you can place the status coming from server for comparison

               //handle fail response
            }
        }
    })
}

Note: You need to ask your backend team to post data in webview using tag with id response_success, if response is success & response_fail, if response is failed.(You can change it as per your requirements)