ios - 从 SafariWebController 返回后出现 Swift 白屏

Question

当我打开 Safari View Controller 然后返回到我的应用程序(按下“完成”时)时，我的应用程序会呈现空白/白色屏幕，而不是该 View 的内容。

下面的代码是我在空 View 中尝试使用的代码 - 无论我在应用程序中的哪个位置尝试，都会出现问题。

import UIKit
import SafariServices

class SavedViewController: UIViewController, SFSafariViewControllerDelegate {

    override func viewDidLoad() {
        super.viewDidLoad()
        // Do any additional setup after loading the view.
        if let link = URL(string: "https://google.com"){
            let myrequest = SFSafariViewController(url: link)
            myrequest.delegate = self
            present(myrequest, animated:true)
        }
    }

    func safariViewControllerDidFinish(_ controller: SFSafariViewController) {
        dismiss(animated:true, completion: nil)
    }

}

网站加载正常，当我返回应用程序时，出现空白屏幕。我做错了什么吗？

Answer 1

它工作正常。您刚刚以这种方式创建了新的 UIViewController，UIViewController 默认情况下具有黑色背景。因此，当您按“完成”时，您只需从 SafariViewController 返回到 SavedViewController (UIViewController)。可能您正在寻找 UIWebView 解决方案 https://developer.apple.com/documentation/uikit/uiwebview .如果您只想显示 SafariViewController 将其作为 ViewController 中的函数来执行，则无需使用 UIViewController 类创建新文件来执行此操作。

import UIKit
import SafariServices

class SavedViewController: UIViewController, SFSafariViewControllerDelegate {

override func viewDidLoad() {
    super.viewDidLoad()
    // Do any additional setup after loading the view.

    view.backgroundColor = .gray
    setupViews()
}

func safariViewControllerDidFinish(_ controller: SFSafariViewController) {
    dismiss(animated:true, completion: nil)
}

private func setupViews(){
    view.addSubview(openSafariButton)
    openSafariButton.addTarget(self, action: #selector(handleOpenSafariButtonTap), for: .touchUpInside)
    openSafariButton.frame = CGRect(x: 0, y: 100, width: view.frame.width, height: 60)
}

@objc func handleOpenSafariButtonTap(){
    if let link = URL(string: "https://google.com"){
        let myrequest = SFSafariViewController(url: link)
        myrequest.delegate = self
        present(myrequest, animated:true)
    }
}

let openSafariButton: UIButton = {
    let button = UIButton()
    button.setTitle("openSafari", for: .normal)
    button.setTitleColor(.black, for: .normal)
    button.backgroundColor = .red
    return button
}()

}

这就是我的意思。

您可以添加功能:

    private func openSafariLink(link: String){
    if let link = URL(string: link){
        let myrequest = SFSafariViewController(url: link)
        present(myrequest, animated:true)
    }
}

并从任何类似的地方调用它:

openSafariLink(link: "https://google.com")

这种方式更适合您的解决方案。