ios - Http post请求没有传递参数？

Question

Hai 我正在尝试在 Http post 请求中传递一些字符串参数。我创建了一个字典，然后将该字典转换为数据并设置为 httpBody。但是当我查看我们的服务器时，没有任何内容被传递，我的意思是参数为空。为什么？我犯了什么错误？请帮我找出答案。提前致谢。

func receiptValidation(productId:String,requestFrom:String)
{
    let SUBSCRIPTION_SECRET = "mySecretKey"
    let defaults = UserDefaults.standard
    let receiptPath = Bundle.main.appStoreReceiptURL?.path
    if FileManager.default.fileExists(atPath: receiptPath!){
        var receiptData:NSData?
        do {
            receiptData = try NSData(contentsOf: Bundle.main.appStoreReceiptURL!, options: NSData.ReadingOptions.alwaysMapped)
        }
        catch{
            print("ERROR: " + error.localizedDescription)
        }
        //let receiptString = receiptData?.base64EncodedString(options: NSData.Base64EncodingOptions(rawValue: 0))
        let base64encodedReceipt = receiptData?.base64EncodedString(options: NSData.Base64EncodingOptions.endLineWithCarriageReturn)

        print(base64encodedReceipt!)
        let requestDictionary = ["receipt-data":base64encodedReceipt!,"password":SUBSCRIPTION_SECRET]

        guard JSONSerialization.isValidJSONObject(requestDictionary) else {  print("requestDictionary is not valid JSON");  return }
        do {
            let requestData = try JSONSerialization.data(withJSONObject: requestDictionary)
            let requestDataString=String(describing: requestData)
            let URLForApplication:String = String(format:"%@/api/validate-receipt-data",opcodeDetails["apiProxyBaseUrl"]!)  // this works but as noted above it's best to use your own trusted server
            SwiftyBeaver.info("URLForApplication Path:\n\(URLForApplication)")
            let url:URL! = URL.init(string: URLForApplication)
            var request = URLRequest.init(url: url)
            request.httpMethod = "POST"
            request.addValue("application/json", forHTTPHeaderField: "Content-Type")
            let configure = URLSessionConfiguration.background(withIdentifier: Bundle.main.bundleIdentifier!)
            session1=URLSession(configuration: .default, delegate: applicationDelegate.application, delegateQueue: OperationQueue.main)

            var postString =
                ["receiptData":requestDataString,
                 "deviceType":"IOS",
                 "subscriberId":encodeString(normalString: defaults.array(forKey: "userDetails")?.first as! String),
                 "password":encodeString(normalString: defaults.array(forKey: "userDetails")?.last as! String),
                 "productId":encodeString(normalString: productId ),
                 "code":opcodeDetails["opCode"]!]
            do {
                request.httpBody = try JSONSerialization.data(withJSONObject: postString, options: .prettyPrinted) // pass dictionary to nsdata object and set it as request body
            } catch let error {
                print(error.localizedDescription)
            }
            request.addValue("application/json", forHTTPHeaderField: "Content-Type")

            let task = session1?.dataTask(with: request) { (data, response, error) in
                if let data = data , error == nil {
                    do {
                        let appReceiptJSON = try JSONSerialization.jsonObject(with: data)
                        print("success. here is the json representation of the app receipt: \(appReceiptJSON)")
                        // if you are using your server this will be a json representation of whatever your server provided
                    } catch let error as NSError {
                        print("json serialization failed with error: \(error)")
                    }
                } else {
                    print("the upload task returned an error: \(error)")
                }
            }
            task?.resume()
        } catch let error as NSError {
            print("json serialization failed with error: \(error)")
        }
    }
}

我收到的错误是Error Domain=NSCocoaErrorDomain Code=3840“JSON文本未以数组或对象开头，并且允许未设置片段的选项。” UserInfo={NSDebugDescription=JSON 文本未以数组或对象开头，并且未设置允许片段的选项。}

Answer 1

你没有说，但我假设你在打印“json 序列化失败并出现错误”时遇到此错误。如果是这样，CZ54 是对的，你的响应显然不是 JSON。因此，在打印该错误的地方，还要打印 header 和正文以查看服务器实际返回的内容(如果有):

print("response header:", response ?? "No response")
print("response body:", String(data: data, using: .utf8) ?? "No body")

响应 header 将包含状态代码(应在 200...299 范围内)。如果不在该范围内，状态代码将告诉您问题的广泛性质。

关于响应正文，有时(特别是在开发环境中)如果服务器因某些原因而阻塞，它可能会返回一个 HTML 页面，概述问题的性质(尽管不可否认，在其他情况下，它只输出以下事实:出现错误，但没有详细信息，您需要进入服务器错误日志以找出问题所在)。

像上面一样，查看回复的具体细节是您的第一步。或者，您可以通过在模拟器上运行应用程序并在 Charles 等工具中观察请求和响应来实现此目的。或Wireshark 。一旦您启动并运行它们，这些都是检查请求和响应的好工具。

下一个问题是为什么服务器生成它所做的响应。一般来说，虽然此类问题可能是由于某些服务器错误造成的，但更可能的情况是请求的格式不正确并且服务器不知道如何处理它。查看响应(或查看服务器的错误日志)通常可以提供很好的线索。但任何人都无法根据所提供的信息为您提供帮助。