php 日期格式返回 01-01-1970

Question

在我的 php 代码中，我在数据库中插入了一些数据。其中之一是日期。我想以 27-08-2016 的格式显示，但我返回 01-01-1970

这是我的代码。

<?php 
include("./init.php");

if(isset($_POST['submit'])){

 $post_game = $_POST['game'];

 $time = strtotime($_POST['date']);

 $post_date = date("d-m-Y", strtotime($time));

if($post_game==''){

    echo "<script>alert('Please fill in all fields')</script>";
    exit();
    }
else {

    $insert_game = "insert into last_game (game,date) values ('$post_game','$post_date')";

    $run_posts = mysqli_query($con,$insert_game); 

        echo "<script>alert('Post Has been Published!')</script>";

        echo "<script>window.open('index.php?last_game_details','_self')   
   </script>";

     }

   }

?> 

关键的一行是:

 $post_date = date("d-m-Y", strtotime($time));

我的 php 版本是:5.6.23

Answer 1

 $time = strtotime($_POST['date']);
    ^-integer             ^---string

$post_date = date("d-m-Y", strtotime($time));
                                ^^^^^^^---useless duplicate call, since you JUST did this anyways