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基于COL2分组的MYSQL Col1 Sum

转载 作者:行者123 更新时间:2023-11-29 05:08:26 25 4
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我正在查询 Wordpress postmeta 表以尝试按客户提取一些销售信息。我怎样才能让客户组合在一起。这里的挑战是所有数据都在 postmeta 表中。

这是我迄今为止不成功的尝试:

SELECT CONCAT_WS(" ", metaA.meta_value, metaB.meta_value) AS customer_name, metaC.meta_value AS 'Total'
FROM wp_postmeta AS metaA
JOIN wp_postmeta AS metaB USING (post_id)
JOIN wp_postmeta AS metaC USING (post_id)
WHERE (metaA.meta_key = '_billing_first_name')
AND (metaB.meta_key = '_billing_last_name')
AND (metaC.meta_key = '_order_total')
GROUP BY metaA.meta_value, metaB.meta_value, metaC.meta_value

结果:

+---------------+---------+
| customer_name | Total |
+---------------+---------+
| customer1 | 10 |
| customer1 | 50 |
| customer1 | 90 |
| customer2 | 40 |
| customer3 | 10 |
| customer3 | 10 |
| customer4 | 20 |
+---------------+---------+

我想得到:

+---------------+---------+
| customer_name | Total |
+---------------+---------+
| customer1 | 150 |
| customer2 | 40 |
| customer3 | 20 |
| customer4 | 20 |
+---------------+---------+

最佳答案

您需要按串联的客户名称进行分组并对 metaC.meta_value 求和:

SELECT CONCAT_WS(" ", metaA.meta_value, metaB.meta_value) AS customer_name, sum(metaC.meta_value) AS 'Total'
FROM wp_postmeta AS metaA
JOIN wp_postmeta AS metaB USING (post_id)
JOIN wp_postmeta AS metaC USING (post_id)
WHERE (metaA.meta_key = '_billing_first_name')
AND (metaB.meta_key = '_billing_last_name')
AND (metaC.meta_key = '_order_total')
GROUP BY CONCAT_WS(" ", metaA.meta_value, metaB.meta_value)

关于基于COL2分组的MYSQL Col1 Sum,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43971996/

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