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Java将数组拆分为范围

转载 作者:行者123 更新时间:2023-11-29 05:05:45 24 4
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使用 Java,我想将一个 int 数组拆分为一个范围数组。比如数组

[1, 2, 3, 4, 5, 6, 7, 8, 100, 101, 102, 103]

会回来

[Range(1, 8), Range(100, 103)]

因为它由1到8和100到103组成

如果有一个库就最好了,但是这种转换的任何一种方法都可以。

最佳答案

好的 James,这是您的工作解决方案 :)

private void executeTestCode(){
int[] arr = new int[]{1, 2, 3, 4, 5, 6, 7, 8, 100, 101, 102, 103};
Range[] ranges = Arrays.stream(getRanges(arr)).filter(r -> r != null).toArray(Range[]::new);
String output = Arrays.stream(ranges)
.map(Range::toString)
.reduce("[", (dynamicString, stringedRange) -> (dynamicString + stringedRange + ", "));
output = output.substring(0, output.length()-2) + "]";
System.out.println(output);
}

输出:
[范围(1, 8), 范围(100, 103)]

private Range[] getRanges(int[] toBeProcessed){
Range[] result = new Range[toBeProcessed.length]; //larger array won't be needed
int startRange = toBeProcessed[0];
int ranges = 0;
for(int a=0; a<toBeProcessed.length; a++){
try{
if(toBeProcessed[a] + 1 != toBeProcessed[a+1]){
result[ranges] = new Range(startRange, toBeProcessed[a]);
startRange = toBeProcessed[a+1];
ranges++;
}
}catch(ArrayIndexOutOfBoundsException e){
result[ranges] = new Range(startRange, toBeProcessed[toBeProcessed.length-1]);
}
}
return result;
}



类别范围:

class Range{
private int start, end;
public Range(int st, int en){
start = st;
end = en;
}

@Override
public String toString(){
return "Range(" +start+ ", " +end+ ")";
}
}

关于Java将数组拆分为范围,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30414845/

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